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3 years ago

Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)? Explain your answer.

Physics

1 answer:

Elden [556K]3 years ago

5 0

Answer: Fluorine

Explanation: The reason being is because... Since Fluorine has a great amount of electromagnetically it reacts at greater amounts. than phosphorus.

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The loudness of sound is determined by what?

baherus [9]

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound

5 0

3 years ago

Read 2 more answers

The temperature of a small metal cube is 75°c. A student places the cube into an insulated container of water at a temperature o

eduard

We can't tell without more information. We know it will be higher than 40 and lower than 75, but we don't know exactly where it will settle. In order to work that out, we would need to know the volumes of the water and the cube, and WHAT metal the cube is made of.

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3 years ago

A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific

dem82 [27]

Answer:

Weight=686.7N, $\rho=933kg/m^{3}$ , S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

$W=70kg(9.81m/s^{2})$

which yields:

W=686.7N

Next, we need to find the density of methanol, which can be found by using the following formula:

$\rho=\frac{m}{V}$

we know the volume of methanol is 75L, so we can convert that to $m^{3}$ like this:

$75L*\frac{0.001m^{3}}{1L}=0.075m^{3}$

so we can now use the density formula to find our the methanol's density, so we get:

$\rho=\frac{m}{V}$

$\rho=\frac{70kg}{0.075m^{3}}$

$\rho=933.33kg/m^{3}$

Next, we can us these values to find the specific gravity of methanol by using the formula:

$S.G.=\frac{\rho_{sample}}{\rho_{H_{2}O}}$

when substituting the known values we get:

$S.G.=\frac{933.33kg/m^{3}}{1000kg/m^{3}}$

so:

S.G.=0.933

We can now find the force it takes to accelerate this tank linearly at $0.25m/s^{2}$

F=ma

$F=(70kg)(0.25m/s^{2})$

F=17.5N

6 0

4 years ago

When a spinning star shrinks in radius, it speeds up. Which of the following statements explains this phenomenon?

Sever21 [200]

Answer:

B.)Angular momentum is always conserved

Explanation:

Angular momentum is given by:

$L=mvr$

where

m is the mass of the object

v is its speed

r is the distance between the object and the centre of its circular trajectory

In absence of external torques, angular momentum is always conserved. That means that for the spinning star, if its radius r decreases (because it shrinks), in order for L (the angular momentum) to be conserved, the speed (v) must increases, therefore the spinning star speeds up.

So, the correct choice is

B.)Angular momentum is always conserved

4 0

3 years ago

A 8.10×10^3 ‑kg car is travelling at 25.8 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 3.9

KengaRu [80]

Answer:

The magnitude of the average drag force is 2412.34 N.

Explanation:

Given that,

Mass of car $m=8.10\times10^{-3}\ kg$

Velocity v = 25.8 m/s

Distance $d= 3.90\times10^{2}$

Speed of car = 13.1 m/s

Height = 12.5 m

We need to calculate the magnitude of the average drag force

Using equation kinetic energy

$K.E_{i}=K.E_{f}+P.E+F_{d}$

$\dfrac{1}{2}mv_{i}^2=\dfrac{}{}mv_{f}^2+mgh+F\times d$

Where, $v_{i}$ = initial velocity

$v_{f}$ = final velocity

h = height

g = acceleration due to gravity

$F_{d}$ =drag force

m = mass of the car

d = distance

Put the value into the formula

$\dfrac{1}{2}\times8.10\times10^{3}\times25.8=\dfrac{1}{2}\times8.10\times10^{3}\times13.1+8.10\times10^{3}\times9.8\times12.5+F\times3.90\times10^{2}$

$F=\dfrac{\dfrac{1}{2}\times8.10\times10^{3}\times25.8-\dfrac{1}{2}\times8.10\times10^{3}\times13.1-8.10\times10^{3}\times9.8\times12.5}{3.90\times10^{2}}$

$F=-2412.34\ N$

$|F|=2412.34\ N$

Hence, The magnitude of the average drag force is 2412.34 N.

4 0

4 years ago