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quester [9]
2 years ago
7

A system consists of a disk rotating on a frictionless axle and a piece of clay moving toward it, as shown in the figure above.

The outside edge of the disk is moving at a linear speed v, and the clay is moving at speed v/2. The clay sticks to the outside edge of the disk. How does the angular momentum of the system after the clay sticks compare to the angular momentum of the system before the clay sticks, and what is an explanation for the comparison?.
Physics
1 answer:
cestrela7 [59]2 years ago
6 0

Explanation:

Forgive me If I am wrong, it's been a while since I've studied Torque.

The formula for the angular momentum is

momentum= I*w.

We can also write I*W as 1/2MR^2 * W so the extra mass coming from the block of clay would most likely cause the angular momentum to increase from the amount it was before.

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At what speed does a 1400 compact car have the same kinetic energy as a 20000 truck going 25 ?
kumpel [21]
K=1400*V^2/2
K=20000*25^2/2. => 1400*V^2/2=20000*25^2/2 <=> 1400*V^2=20000*25^2
14*V^2=200*225
v^2=100*225/7
v=250/7^(1/2)

Answer: 250*7^(1/2)/7
4 0
3 years ago
a car was traveling at 30.0 m/s when a small child darted onto the road 60.0 m away. Reacting instantly the driver slams the bra
Galina-37 [17]
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2 years ago
HELP PLEASE AND HURRRRRY
kykrilka [37]

Answer:

the path the object follows is called its trajectory so A. trajectory

6 0
3 years ago
A(n) 72.6 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 48.1 m away from the shuttle
netineya [11]

Answer:

The time taken to get the shuttle is 6.91 minutes.

Explanation:

Given that.

Mass of an astronaut, m_1=72.6\ kg

Distance between astronaut and shuttle, d = 48.1 m

Mass of the camera, m_2=0.704\ kg

Speed of camera, v = 12 m/s

We need to find the time taken by the astronaut to reach her shuttle. Both shuttle and astronaut are at rest, their initial velocities will be equal to 0. Using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\m_1(0)+m_2(0)=m_1v_1+m_2v_2\\\\m_1v_1+m_2v_2=0\\\\v_1=\dfrac{-m_2v_2}{m_1}\\\\v_1=\dfrac{0.704\times 12}{72.6}\\\\v_1=0.116\ m/s

The time taken to get the shuttle is given by :

t=\dfrac{d}{v_1}\\\\t=\dfrac{48.1}{0.116}\\\\t=414.65\ s

or

t = 6.91 minutes

So, the time taken to get the shuttle is 6.91 minutes.

3 0
2 years ago
A 40.9 kg satellite circles planet Cruton every 5.82 h. The magnitude of the gravitational force exerted on the satellite by Cru
iragen [17]

Answer:

r = 2.8524 x10⁷ m = 28524 km

Explanation:

First, we calculate the angular speed of the satellite:

\omega = \frac{Arc Length}{Time}\\\\For\ One\ Complete\ Revolution\ around\ Cruton:\\\\\omega = \frac{2\pi\ rad}{5.82\ h}\frac{1\ h}{3600\ s}\\\omega =  3\ x\ 10^{-4} rad/s

Now, we use the formula for the gravitational force. Since gravitational force will be acting as the centrifugal force due to circular motion. Therefore,

F = \frac{mv^{2}}{r}\\

where,

F = Gravitational Forc = 105 N

m = mass of satellite = 40.9 kg

v = linear speed of satellite = rω = r(3 x 10⁻⁴ rad/s)

r = radius of orbit = ?

Therefore,

105\ N = \frac{(40.9\ kg)(r*3\ x\ 10^{-4}\ rad/s)^{2}}{r}\\r = \frac{105}{(40.9)(9\ x\ 10^{-8})}  \\

<u>r = 2.8524 x10⁷ m = 28524 km</u>

5 0
2 years ago
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