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kompoz [17]
3 years ago
13

A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo

nument. A nickel with a mass of 0.005 kg is in her shirt pocket. What is the gravitational potential energy (GPE) of the nickel at the top of the monument?
Physics
2 answers:
REY [17]3 years ago
8 0

Answer:

GPE ≈ 8.3 J

Explanation:

m = 0.005 kg

g = 9.80 m/s2

h = 169.164 m

GPE =?

GPE = mgh

GPE = (0.005 kg)(9.8 m/s2)(169.164 m)

GPE = 8.289 (kg)(m/s2)(m)

GPE = 8.289 (kg)(m2/s2)

GPE = 8.289 J

GPE ≈ 8.3 J  

Svetllana [295]3 years ago
7 0

Answer:

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

Explanation:

We can find the gravitational potential energy using the following  formula.

GPE=mgh

Identifying given information.

The nickel has a mass m=0.005 \,kg, and it is a the top of Washington Monument.

The Washington Monument has a height of h=555 \, ft, thus we need to find the equivalence in meters using unit conversion in  order to find the gravitational potential energy.

Converting from feet to meters.

Using the conversion factor 1 m = 3.28 ft, we have

h = 555 \, ft \times \cfrac{1 \, m}{3.28 \, ft}

That give u s

h = 169.2 \, m

Finding Gravitational Potential Energy.

We can replace the height and mass on the formula

GPE=mgh

And we get

GPE=(0.005)(9.8)(169.2) \, J

\boxed{GPE=8.29 \,J}

The gravitational potential energy of the nickel at the top of the monument is 8.29 J.

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melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

4 0
2 years ago
Which image represents the force on a positively charged particle caused by an approaching magnet?
Amanda [17]

Answer:

Image B represents the force on a positively charged particle caused by an approaching magnet.

Explanation:

The most fundamental law of magnetism is that like shafts repulse each other and dissimilar to posts pull in one another; this can without much of a stretch be seen by endeavoring to put like posts of two magnets together. Further attractive impacts additionally exist. On the off chance that a bar magnet is cut into two pieces, the pieces become singular magnets with inverse shafts. Also, pounding, warming or winding of the magnets can demagnetize them, on the grounds that such dealing with separates the direct game plan of the particles. A last law of magnetism alludes to maintenance; a long bar magnet will hold its magnetism longer than a short bar magnet. The domain theory of magnetism expresses that every single enormous magnet involve littler attractive districts, or domains. The attractive character of domains originates from the nearness of significantly littler units, called dipoles. Iotas are masterminded in such a manner in many materials that the attractive direction of one electron counteracts the direction of another; in any case, ferromagnetic substances, for example, iron are unique. The nuclear cosmetics of these substances is with the end goal that littler gatherings of particles unite as one into zones called domains; in these, all the electrons have the equivalent attractive direction.

4 0
2 years ago
You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi
Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

      E_A} =E_{B}

     Spring potential energy =potential energy due to elevation

   0.5*k*x²= mg(h_{B}-h_{A} )=mgh

   0.5*k*2.3²= 430*9.81*6

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For safety reason

                                 k"=1.13 *k= 1.13*9568.92

                                    k"=10812.88 N/m

agsin from conservation of energy

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    spring potential energy=change in kinetic energy

   0.5*k"*x²=0.5*m*V_{max}^{2}

      10812.88 *2.3²=430*V_{max}^{2}

           V_{max}=11.53 m/s

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Rx= 3.5 km

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nadya68 [22]

Answer:

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Kinetic energy at bottom of slide:

= (1/2) M v^2 = 52.5 J

5 0
3 years ago
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