Answer:
The direction will be 
and the distance 250.75km.
Explanation:
Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:
The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):
If 
is the direction of R then:
⇒ 
⇒ 
.
The distance will be given by the magnitud of the vector R:
⇒ 
.
50 times 2.5 and them subract the product from 2500
I THINK THAT IS THE ANSWER
HOPE THIS HELPS!!!!!!! ;-)
Answer:
See attached document
Explanation:
Entire process for deriving the asked expression dV across the bridge as function of dP is illustrated in the attachment below.
The document gives a step-by step process for arriving at the expression. However, manipulation of algebraic equations is skipped for the conciseness of the document.
It also gives the expression for the case when all resistors have different nominal values.
It’s c “ the same size as you are”
Answer:
3.3m/s
Explanation:
You first get the total time (80 + 70 = 150s).
Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.
d= 500m.
So now that you have displacement and time, you can find the velocity:
v=d/t
v=500/150
v=3.3
