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3 years ago

Determine the magnitude of force F so that the resultant FR of the three forces is as small as possible.

Physics

1 answer:

Kamila [148]3 years ago

8 0

Answer: FR=2.330kN

Explanation:

Write down x and y components.

Fx= FSin30°

Fy= FCos30°

Choose the forces acting up and right as positive.

∑(FR) =∑(Fx )

(FR) x= 5-Fsin30°= 5-0.5F

(FR) y= Fcos30°-4= 0.8660-F

Use Pythagoras theorem

F2R= √F2-11.93F+41

Differentiate both sides

2FRdFR/dF= 2F- 11.93

Set dFR/dF to 0

2F= 11.93

F= 5.964kN

Substitute value back into FR

FR= √F2(F square) - 11.93F + 41

FR=√(5.964)(5.964)-11.93(5.964)+41

FR= 2.330kN

The minimum force is 2.330kN

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Aleksandr-060686 [28]

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Explanation:

Given

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Once the crate is set in motion 56 N is require to move it with constant velocity

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3 years ago

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W = -1844.513 J

Explanation:

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change in displacement is = -6.753 - (-11) = 4.25 m

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$W = 725.2 \times 4.25 \times cos 180$

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