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Darya [45]
3 years ago
6

Suppose you were given a substance and asked to determine whether or not it was a plasma. Write the characteristics you would lo

ok for to identify the substance.
Chemistry
2 answers:
Blababa [14]3 years ago
7 0
Plasma is basically ionized gas. Therefore, one easy test would be to check the ability of the substance to carry electric current.
katovenus [111]3 years ago
5 0

Answer is: electrical conductivity, temperature, electromagnetism.

Plasma is a an ionised gas with highly electrical conductivity.

It is an electrically neutral with positive and negative particles.

Plasma may be the most abundant form of matter in the universe.

Plasma was first described by chemist Irving Langmuir.

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What is the smallest part of an element that still retains properties of that element?
Leni [432]
The smallest part is the atom
4 0
3 years ago
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A 120.5 g sample of water loses -7525 J of energy. What was the
dusya [7]

Answer:14.93

Explanation:heat gained=heat lost

120.5 ×4.184×change=7525

7525÷504.172

Ans14.925

5 0
4 years ago
A cell was prepared by dipping a Cu wire and a saturated calomel electrode into 0.10 M CuSO4 solution. The Cu wire was attached
Rashid [163]

Answer:

(a)  Cu²⁺ +2e⁻ ⇌ Cu

(c) 0.07 V  

Explanation:

(a) Cu half-reaction

Cu²⁺ + 2e⁻ ⇌ Cu

(c) Cell voltage

The standard reduction potentials for the half-reactions are+

                                             <u> E°/V </u>

Cu²⁺ + 2e⁻ ⇌ Cu;                  0.34  

Hg₂Cl₂ + 2e⁻ ⇌ 2Hg + 2Cl⁻; 0.241

The equation for the cell reaction is

                                                                            E°/V

Cu²⁺(0.1 mol·L⁻¹) + 2e⁻ ⇌ Cu;                               0.34  

<u>2Hg + 2Cl⁻ ⇌ Hg₂Cl₂ + 2e⁻;                             </u> <u>-0.241 </u>

Cu²⁺(0.1 mol·L⁻¹) + 2Hg + 2Cl⁻ ⇌ Cu + Hg₂Cl₂;   0.10

The concentration is not 1 mol·L⁻¹, so we must use the Nernst equation

(ii) Calculations:  

T = 25 + 273.15 = 298.15 K

Q = \dfrac{\text{[Cl}^{-}]^{2}}{ \text{[Cu}^{2+}]} = \dfrac{1}{0.1} = 10\\\\E = 0.10 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(10)\\\\=0.010 -0.01285 \times 2.3 = 0.10 - 0.03 = \textbf{0.07 V}\\\text{The cell potential is }\large\boxed{\textbf{0.07 V}}

 

3 0
3 years ago
A block of material has a volume of 50 cubic centimeters, and a mass of 1,000 grams; what is that object's density?
zhannawk [14.2K]

Answer:

Density = 20\ g/cm^3

Explanation:

Given that,

Mass of the object, m = 1000 g

Volume of the block, V = 50 cm³

We need to find the density of the object. Density is equal to mass per unit volume.

d = m/V

d=\dfrac{1000\ g}{50\ cm^3}\\\\=20\ g/cm^3

So, the density of the object is 20\ g/cm^3.

8 0
3 years ago
Electrons orbit the nucleus like planets around the sun.​<br>true or false?
gogolik [260]

Answer: true

Explanation: Electrons orbit the nucleus of an atom the way that planets revolve around the Sun. The electrons are like the planets in the solar system. The sun is like the nucleus in the solar system. The answer to the question is true.

7 0
3 years ago
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