Answer:
Self inductance, 
Explanation:
It is given that,
Length of the coil, l = 5 cm = 0.05 m
Area of cross section of the coil, 
Number of turns in the coil, N = 130
The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :
L = 0.000127 Henry
or
So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.
Answer:
(a) 0.33 second
(b) 6 cm/s
Explanation:
Frequency, f = 3 waves per second
wavelength, λ = 2 cm = 0.02 m
(a) The period of wave is defined as the time taken by the wave to complete one oscillation. It is the reciprocal of frequency.
T = 1 / f = 1 / 3 = 0.33 second
(b) the relation between wave velocity, frequency and wavelength is given by
v = f x λ
v = 3 x 0.02 = 0.06 m /s
v = 6 cm /s
Answer: 0.213m
Explanation: The fundamental frequency is 805Hz.
The second harmonic (first overtone ) is 1035 Hz and the third harmonic (second overtone) is 1265 Hz.
The pipe is an air filled hence it is a closed pipe
Recall that v = f λ
At fundamental frequency
Where v = speed of sound in air (v) = 343 m/s
Fundamental frequency (f) = 805 Hz
Wavelength ( λ) = ?
By substituting the parameters, we have that
343 = 805 × λ
λ = 343 / 805
λ = 0.426m
The pipe is an open one and at the fundamental frequency, hence the relationship between wavelength ( λ) and length of air is given as
L = λ/4
But λ = 0.426m
L = 0.426/2
L = 0.213m
Explanation:
If the intensity of the yellow light increased, meaning more photons will strike the Potassium metal per unit area. This will cause more ejection of electrons from the metal and hence, the strength of current will also increase as we know that
I = Q/t, as the charge increase , the current will also increase.
