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Alex777 [14]
3 years ago
8

A marble rolls across a table for 6 meters in 2.3 seconds. What is the velocity of the marble?

Physics
2 answers:
inn [45]3 years ago
7 0

Answer:

\boxed {\tt v\approx2.61 \ m/s}

Explanation:

Velocity can be found by dividing the displacement by the time.

v=\frac{d}{t}

The displacement is 6 meters and the time is 2.3 seconds.

d= 6 \ m\\t= 2.3 \ s

Substitute the values into the formula.

v=\frac{6 \ m}{2.3 \ s}

Divide.

v=2.60869565 \ m/s

Let's round to the nearest hundredth. The 8 in the thousandth place tells us to round the 0 to a 1.

v\approx2.61 \ m/s

The velocity of the marble is about 2.61 meters per second.

monitta3 years ago
5 0

Answer:

2.61 \frac{m}{s}

Explanation:

v= d/t

v = 6m/2.3 s

v=2.61 \frac{m}{s}

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Answer:

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Explanation:

<u>Identify the unknown:  </u>

The work required to turn the dial from 180° to 0°  

<u>List the Knowns:  </u>

Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F  

Voltage of the battery: V = 130 V  

<u>Set Up the Problem:</u>  

<em><u>Energy stored in a capacitor: </u></em>

U_c=1/2*V^2*C

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<em><u>When the dial is set at 180°:</u></em><em>  </em>

U_c=1/2*(130)^2*350*10^-12=10^-4

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<u><em>When the dial is set at 0°:</em></u>  

U_c=1/2*(4*10^-7)^2/100*10^-12

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