Question

Iron crystallizes in a body-centered cubic cell having an edge length of 287 pm. What is the density of iron in g/cm3.

Answer 1

Answer:The density of iron in $0.0784 g/cm^3$

Explanation:

The density of the crystal solids is calculated by using :

$\rho=\frac{Z\times M}{N_A\times a^3}$

Z = number of atoms in crystal lattice  in body centered cubic cell = 2

M = Atomic mass  = 55.85 g/mol

a = Edge length of the crystal  = 287 pm = $287\times 10^{-10}cm$

$1 pm=1\times 1-^{-10} cm$

$\rho=\frac{2\times 55.85 g/mol}{6.022\times 10^{23}\times (287\times 10^{-10}cm)^3}$

$\rho=0.0784 g/cm^3$

The density of iron in $0.0784 g/cm^3$