Question

A 1.10 M HCl solution prepared from 190.0 mL of a 7.0 M HCl

Answer 1

Answer:

1,209mL or 1.209L

Explanation:

For this equation you would use M1V1=M2V2

You would plug (1.10M)( XmL)=(7.0M)(190.0mL)

Then you would solve for X

XmL= $\frac{(7.0M)(190.0mL)}{1.10M}$

XmL- 1,209mL