All categories

3 years ago

Where is the magnetic field of point P pointed

Physics

1 answer:

lisov135 [29]3 years ago

8 0

Field lines point in the direction that leaves north and enters south. So at P they are pointing toward C since it's in the direction of the south pole of the magnet

You might be interested in

The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an

Marrrta [24]

Answer: $k=55.590 KN/m$

Explanation:

Given

mass of person $\left ( m\right )$ =68 kg

car dips about 1.2 cm

We know

F=kx

Where k=combined spring constant

mg=kx

$k=\frac{mg}{x}$

$k=\frac{68\times 9.81}{1.2\time 10^{-2}}$

$k=55.590 KN/m$

7 0

3 years ago

4. True or false: Ionic<br> Compounds do not form<br> molecules.

Verizon [17]

Answer:

true

Explanation:

ionic compounds do not form molecules

7 0

2 years ago

Read 2 more answers

Scientists might model the water cycle by using a diagram. What are two

natta225 [31]

Answer: A and B

Explanation: it says benefits and the other two are not benefits.

5 0

3 years ago

A bowling ball has a mass of 5 kg. What happens to its momentum when its speed increases from 1 m/s to 2 m/s?

faltersainse [42]

The linear momentum is given by $mv$ . Here $m$ is mass $v$ is velocity of the body. Given mass and velocities as $m=5,v_i=1,v_f=2$

Initial momentum is $mv_i=5*1=5$ and final momentum is $mv_f=5*2=10$ .

The correct answer is (A)

8 0

3 years ago

A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo

Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

Speed of object 1, v₁ = 2 m/s

Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

$E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2$

$E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2$

E = 9 J

So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

3 0

2 years ago