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seraphim [82]
3 years ago
13

Where is the magnetic field of point P pointed

Physics
1 answer:
lisov135 [29]3 years ago
8 0
Field lines point in the direction that leaves north and enters south.  So at P they are pointing toward C since it's in the direction of the south pole of the magnet
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A machine produces 4,000 J of work in 5 seconds. how much power does the machine produce.
ad-work [718]

Explanation:

Power is defined as the work done per unit time or

P = \dfrac{\Delta W}{\Delta t}

\;\;\;\;= \dfrac{4000\:\text{J}}{5\:\text{s}} = 800\:\text{Watts}

5 0
2 years ago
An alternating current is supplied to an electronic component with a rating that the voltage across it can never, even for an in
Vsevolod [243]

Answer:

A) V_{rms}=8\sqrt{2} V

Explanation:

Maximum voltage =V_{max}=16 V

Maximum voltage and rms voltage are related to each other by

V_{max}=V_{rms} \times \sqrt{2} \\V_{rms}=\frac{V_{max}}{ \sqrt{2}}\\V_{rms}=\frac{16}{\sqrt{2}} \\V_{rms}=8\sqrt{2} V

7 0
3 years ago
A resistor with an unknown resistance is connected in parallel to a 13 ? resistor. when both resistors are connected in parallel
DENIUS [597]
Hope this helps you.

4 0
3 years ago
Excellent human jumpers can leap straight up to a height of
Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.  

We can calculate the initial speed to reach 110 cm of height with the following equation:

v_{f}^{2} = v_{i}^{2} - 2gh

Where:

v_{f}: is the final speed = 0 (at the maximum height of 110 cm)

v_{i}: is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the <u>initial velocity</u> is:

v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0
2 years ago
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
labwork [276]

Answer:

9.4 m/s

Explanation:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in kinetic energy of the system.

Therefore we can write:

W=K_f -K_i

where in this case:

W = -36,733 J is the work done by the parachute (negative because it is opposite to the motion)

K_i = 66,120 J is the initial kinetic energy of the car

K_f is the final kinetic energy

Solving,

K_f = K_i + W=66,120+(-36,733)=29387 J

The final kinetic energy of the car can be written as

K_f = \frac{1}{2}mv^2

where

m = 661 kg is its mass

v is its final speed

Solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s

4 0
3 years ago
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