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irinina [24]
3 years ago
12

A well-known transform boundary found in California is the _____.

Physics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

A well-known transform boundary found in California is the San Andreas fault.

larisa [96]3 years ago
3 0

Answer:

A well-known transform boundary found in California is the San Andreas fault. Explanation; The San Andreas Fault is the most famous fault in the world.The San Andreas Fault is a place where two tectonic plates touch, the North American and Pacific Plates.

Explanation:

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Determine the density of a rectangular piece of concrete that measures 3.7 cm by 2.1 cm by 5.8 cm and has a mass of 43.8 grams.
Novay_Z [31]
It is customary to work in SI units.

Calculate the volume of the concrete.
V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³

The mass is  43.8 g = 43.8 x 10⁻³ kg

The density is mass/volume.
Density = (43.8 x 10⁻³ kg)/(45.066 x 10⁻⁶ m³) = 971.9 kg/m³

Answer: 971.9 kg/m³
5 0
3 years ago
A periodic wave has a fixed pattern that is repeated. What is one completion of the wave pattern called?
Kaylis [27]
It is called cycle. Letter D
7 0
3 years ago
In a solid , the atoms are tightly locked in position an do not change posistion , true or false
attashe74 [19]
the answer is true because they're so close together that they can't move they can't slide past each other or anything
6 0
4 years ago
An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the el
ira [324]

Answer:

The electric field is E = 5.1*10^6N/C.

Explanation:

The force F on a charge q in an electric field E is given by

F = qE,

which can be rearranged to give

E = \dfrac{F}{q }

Now, the force on the electron is F = 8.30*10^{-13}N, and its charge is

q = 1.6*10^{-19}C; therefore,

E = \dfrac{8.30*10^{-13}N}{1.6*10^{-19}C}

\boxed{E = 5.1*10^6N/C}

4 0
3 years ago
The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.
dmitriy555 [2]
The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get, 

<span>d = [n*MW]/ Na*[a^3] 
</span><span>d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3] 
</span>d = 0.719 g/cm3
4 0
4 years ago
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