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3 years ago

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Chemistry

1 answer:

dalvyx [7]3 years ago

6 0

Is this english or whattttt

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Which of the following is a way that crystals can form in nature

Leona [35]

I only knwi one way which is if water evaporates from a mixture

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4 years ago

How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?

shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically, molarity = $\frac{no. of moles}{Volume (in L) of solution}$

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

molarity = $\frac{no. of moles}{Volume of solution in liter}$

0.0800 M = $\frac{no. of moles}{0.05 L}$

no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

No. of moles = $\frac{mass in grams}{molar mass}$

mass in grams = $no. of moles \times molar mass of CuSO_{4}.5H_{2}O$

= $1.6 mol \times 249.68 g/mol$

= 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0

3 years ago

Julie was working on homework and was asked to name the formula, SnS2. She wrote down

Alex787 [66]

She forgot to put (II) it should be tin(II)sulfide

7 0

3 years ago

Americium-241 undergoes radioactive decay to produce neptunium-237. Which particle needs to be added to this equation to show th

nikitadnepr [17]

Answer:

alpha particle needs to be added to the equation.

Explanation:

Given;

atomic mass of Americium = 241

atomic mass of neptunium = 237

The difference in atomic mass of the radioactive elements given is calculated as;

241 - 237 = 4

The particle with atomic mass of 4 is alpha particle usually represented with helium atom.

Am²⁴¹ -----> He⁴ + Np²³⁷

Thus, alpha particle needs to be added to the equation.

7 0

3 years ago

Read 2 more answers

How many milliliters of a 0.15--M solution of KOH will be reuired to titrate 40.00mL of a 0.656-M solution of H3PO4?

pychu [463]

<u>Answer:</u> The volume of HBr solution required is 542.8 mL

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $KOH$

We are given:

$n_1=3\\M_1=0.656M\\V_1=40mL\\n_2=1\\M_2=0.15M\\V_2=?mL$

Putting values in above equation, we get:

$3\times 0.656\times 40=1\times 0.15\times V_2\\\\V_2=542.8mL$

Hence, the volume of KOH solution required is 542.8 mL

6 0

3 years ago