What is the latitude and longitude of the copper mine in Wisconsin (WI)?

Can someone please tell me...... What does it mean if you through up thew your nose and mouth at the same time!?

hodyreva [135]

if you're worried about youre health you're completely fine. (other than the fact you are throwing up, if your sick please see a doctor) but if the things you're worried about is that it can out of your nose, dont worry it happenes to a lot of people. Your nose and mouth are both connected to your throat and that sudden rush of fluids from your throat can confuse your body, Its like when you laugh while eating and then you accidently get food in your nose. Don't worry this isn't anything that is particulary bad but i will say that the vomiting is not good

3 0

4 years ago

Read 2 more answers

I will mark you brainlist please help

denis-greek [22]

Answer:15th

Explanation:

I believe it will fall on the 15th stair because 10 times 15 is 150 divided by 10 m/s equals 15

8 0

3 years ago

A 64.1 kg runner has a speed of 3.10 m/s at one instant during a long-distance event.(a) What is the runner's kinetic energy at

Liono4ka [1.6K]

Answer:

(a) the runner's kinetic energy at the given instant is 308 J

(b) the kinetic energy increased by a factor of 4.

Explanation:

Given;

mass of the runner, m = 64.1 kg

speed of the runner, u = 3.10 m/s

(a) the kinetic energy of the runner at this instant is calculated as;

$K.E_i = \frac{1}{2} mu^2\\\\K.E_i = \frac{1}{2} \times 64.1 \times 3.1^2\\\\K.E_i = 308 \ J$

(b) when the runner doubles his speed, his final kinetic energy is calculated as;

$K.E_f = \frac{1}{2} mu_f^2\\\\K.E_f = \frac{1}{2} m(2u)^2\\\\K.E_f = \frac{1}{2} \times 64.1 \ \times (2\times 3.1)^2\\\\K.E_f = 1232 \ J$

the change in the kinetic energy is calculated as;

$\frac{K.E_f}{K.E_i} = \frac{1232}{308} =4$

Thus, the kinetic energy increased by a factor of 4.

4 0

3 years ago

The position of a ball is given by x(t) (2.3 m/s) .t + (5.3m/s3) t3. What is the position 348 m at time t 4 s? You are correct Y

Georgia [21]

Answer:

(a) 348.4 m

(b) 256.7 m/s

(c) 127.2 m/s^2

Explanation:

$x = 2.3 t + 5.3 t^{3}$

(a) at t = 4 s

x = 2.3 x 4 + 5.3 x 4 x 4 x 4

x = 348.4 m

(b) The derivative of displacement function gives the value of instantaneous velocity.

So, v = dx / dt = 2.3 + 5.3 x 3 x t^2

v = 2.3 + 15.9 t^2

Put t = 4 s

So, v = 2.3 + 15.9 x 4 x 4

v = 256.7 m/s

(c) The derivative of velocity function with respect to time gives the value of instantaneous acceleration.

So, a = dv / dt = 5.3 x 3 x 2 x t

a = 31.8 t

Put t = 4 s

a = 31.8 x 4 = 127.2 m/s^2

4 0

4 years ago

Electrically neutral objects cannot exert an electrical force on each other, but they can exert a gravitational force on each ot

Olenka [21]

The correct answer is
A) true

In fact, the electrical force can be present only if the two objects have a net charge different from zero, because the electrical force is proportional to the value of the charges:
$F_e = k_e \frac{Q_1 Q_2}{r^2}$
so, if they are neutral they cannot exert an electrical force between each other, because their charge Q is zero.

Viceversa, the gravitational force is always present when the objects have masses, since the force is proportional to the value of the masses:
$F_g = G \frac{m_1 m_2}{r^2}$
so, even if the two objetcs are neutral, if they have mass, they exert a gravitational force to each other.

4 0

4 years ago