If Earth rotated twice as fast as it currently does, but is motion around the Sun stayed the same, then ___

A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha

allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

$d=2.2i+cj$

While the force applied on the particle is

$F=3.2i-3.8 j$

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

$W=F\cdot d$ (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

$0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85$

b)

In this problem, the work done on the particle is

$W=4.0 J$

The force and displacement are still

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

$W=F\cdot d$

$4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8$

c)

In this problem instead, the work done on the particle is negative:

$W=-1.8 J$

As before, the force and displacement are

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

And so again, we calculate the scalar product between force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

$W=F\cdot d$

$-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33$

7 0

3 years ago

Do you have to take physics to graduate high school?

Lina20 [59]

Usually, you have to take two years of physical sciences with lab. It doesn't have to be physics, it can be chemistry or biology.

6 0

3 years ago

30 POINTS!!! I need help ASAP, if someone comments just for points, or is incorrect just for points I will report! Please help!!

Anika [276]

Answer:

1.) answer B

2.) answer D

3.) answer A

Explanation:

In all of these problems, it is essential to draw pictures in order to understand which trigonometric function to use according to the angle that the vector in question forms with the component requested. For all of them try to picture a right angle triangle with the vector as the hypotenuse, and the components as the triangle's shorter sides. Please refer to the three pictures attached as image for this answer a,d notice that the vector quantity known for all cases is represented in red, and the component to find is represented in green.

Problem 1) : the vector velocity makes an angle of 24 degrees with the edge of the table. So picture that vector as the hypotenuse of a right angle triangle for which you know the value: 1.8 m/s

So in this case, where you know the angle, the hypotenuse, and need to find the adjacent side to the angle, you use the cosine function as follows:

requested component $=1.8 * cos (24) =1.644 \frac{m}{s}$

which we round to 1.6 to match answer C).

For problem 2.) wee need to find the component opposite to the given angle in the triangle for which we also know the hypotenuse. So we use the sine function as follows:

requested component $=150 * sin(65) = 135.94 m$

which we round to 135.9 m to match answer D).

For problem 3.) we need to find the horizontal component to the acceleration which corresponds to the adjacent side to the known angle, so we use the cosine function as follows:

requested component $=12 *cos(50) = 7.71 \frac{m}{s^2}$

which we round tp 7.7 to match answer A).

7 0

4 years ago

A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented

oee [108]

Answer:

Magnetic flux, $\phi=2.22\times 10^{-3}\ Wb$

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

$\phi=BA\ cos\theta$

$\phi=0.078\times \pi \times (0.1)^2\ cos(25)$

$\phi=0.00222\ Wb$

or

$\phi=2.22\times 10^{-3}\ Wb$

So, the magnitude of magnetic flux through the surface is $2.22\times 10^{-3}\ Wb$ . Hence, this is the required solution.

4 0

3 years ago

when a person uses an iron to remove wrinkles from a shirt why does heat travel to the iron to the shirt

steposvetlana [31]

<u>Explanation</u>
The Iron is incontact with the shirt. So, heat is transferred from the iron to the shirt because they are in contact.
Before the contact, there is temperature difference between the shirt and the iron. When they come into contact there must be exchange of heat energy, this happens until equilibrium state is reach.

7 0

3 years ago

Read 2 more answers

If Earth rotated twice as fast as it currently does, but is motion around the Sun stayed the same, then ____.