Question

A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C with no change in volume. Calculate the final pressure of the gas. P = atm

Answer 1

Answer:

$0.904 atm$

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = $\frac{0.979 atm * 314k }{340k}$

P₂ = $0.904 atm$