Answer:
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Explanation:
given data:
Pressure P = 3 * 10^ 5 Pa
speed v = 5 m / s
Area A = A
from the information given in equation final Area is 1/3 of initial area i.e.
A ' = A / 3
we know that density of water = 1000 kg / m^ 3
from continuity equation
Av = A ' v'
so we have
speed v ' = 3*A*v / A
v ' = 3*A*5/ A
v = 15 m / s
from bernoulli's equation we can calculate final pressure
Required pressure P ' = P + ( 1/ 2) \rho [ v^ {2} v'^{ 2}]
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The frequency of bird chirping hear by hiran will be 1.77 kHz.
<u>Explanation:</u>
As per Doppler effect, the observer will feel a decrease in the frequency of the receiving signal if the source is moving away from the observer. So the shifted frequency is obtained using the below equation:
Here , c is the speed of sound, Vs is the velocity of source with which it is moving away. f is the original frequency of source and f' is the frequency shift heard by the observer.
As here, f = 1800 Hz, Vs= 6 m/s and c = 343 m/s, then
So, the frequency of bird chirping hear by hiran will be 1.77 kHz.