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icang [17]
4 years ago
14

If a neutral object such as paper comes close to a positively charged plastic rod, what type of charge accumulates on the side o

f the paper closest to the positive rod? a positive charge a negative charge a neutral charge an equal number of positive and negative charges
Physics
2 answers:
goblinko [34]4 years ago
6 0
The appropriate response is the negative charge owing fascination of positive charge of the plastic street. Particles are comprised of protons, neutrons, and electrons. Neutrons are unbiased and don't have any charge whatsoever. Protons convey a positive charge, and electrons convey the negative charge. At the point when a question has a positive charge, it has a bigger number of protons than electrons.
rodikova [14]4 years ago
5 0

Answer:

A negative charge

Explanation:

When a positively charged object is bought near to the netral object then by the process of induction the neutral object acquires a charge opposite to the charged body.

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Flapping flight is very energy intensive. A wind tunnel test
steposvetlana [31]

Answer:

The metabolic power for starting flight=134.8W/kg

Explanation:

We are given that

Mass of starling, m=89 g=89/1000=0.089 kg

1 kg=1000 g

Power, P=12 W

Speed, v=11 m/s

We have to find the metabolic power for starting flight.

We know that

Metabolic power for starting flight=\frac{P}{m}

Using the formula

Metabolic power for starting flight=\frac{12}{0.089}

Metabolic power for starting flight=134.8W/kg

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4 0
3 years ago
A soccer field is viewed from above, while a ball is kicked eastward with an initial speed of 10.0 m/s. The ball experiences a c
satela [25.4K]

Answer:

the ball travelled approximately 60 m towards north before stopping

Explanation:

 Given the data in the question;

First course : a_{x} = 0.75 m/s², d_{x} = 20 m, u_{x} = 10 m/s

now, form the third equation of motion;

v² = u² + 2as

we substitute

v_{x}² = (10)² + (2 × 0.75 × 20)

v_{x}² = 100 + 30

v_{x}² = 130

v_{x} = √130

v_{x} = 11.4 m/s

for the Second Course:

u_{y} =  11.4 m/s,  a_{y} = -1.15 m/s²,  v_{y} = 0

Also, form the third equation of motion;

v² = u² + 2as

we substitute

0² = (11.4)² + (2 × (-1.15) ×  d_{y} )

0 = 129.96 - 2.3d_{y}

2.3d_{y}  = 129.96

d_{y} = 129.96 / 2.3

d_{y} = 56.5 m

so;

|d| = √( d_{x}² + d_{y}² )

we substitute

|d| = √( (20)² + (56.5)² )

|d| = √( 400 + 3192.25 )

|d| = √( 3592.25 )

|d| = 59.9 m ≈ 60 m

Therefore, the ball travelled approximately 60 m towards north before stopping

7 0
2 years ago
In most cases, magma differentiation (a.k.a. fractional crystallization produces magma with higher ___________ content than the
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4 years ago
"When fire stopping material is used where more than ____________________ nonmetallic sheathed cables pass through wood framing
GenaCL600 [577]

Answer: When fire stopping material is used where more than 2 non-metallic sheathed cables pass through wood framing members, their ampacities must be adjusted, according to 310.15"

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What would happen if we do not eat body building food?​
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Answer:

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Explanation:

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