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Ilya [14]
3 years ago
9

When Maggie applies the brakes of her car, the car slows uniformly from 15.3 m/s to 0 m/s in 2.23 s. How far ahead of a stop sig

n must she apply her brakes in order to stop at the sign? Answer in units of m
Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

The answer is 34.119m

Explanation:

You need to pay attention to the word "uniformly". It means there is no acceleration thus the physics of this problem respond to the uniform rectilinear motion equations:

  • Xf = Xo + vt
  • v = constant
  • a = 0

where:

  • Xf = Final position
  • Xo = Origin position
  • v = velocity (speed)
  • t = time
  • a = acceleration

Xf = 0 + (15.3)(2.23)

Xf = 34.119m

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Hatshy [7]

Answer:

W = 46 J

Explanation:

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First we will find the angle α of the force vector

tan\alpha =\frac{1}{8} \\\\\\alpha =7.125 deg\\

Then we find the angle β of the displacement vector

tan\beta=\frac{2}{6} \\\\beta = 18.43 deg\\

With these two angles we can find the angle between the two vectors

∅ = α + β = 25.56 deg

The definition of work is given by the expression

W=F*d*cos (theta)

The absolute value of F will be:

F=\sqrt{8^{2}+1^{2}  } \\F= 8.06 N

The absolute value of d will be:

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Now we have:

W=8.06*6.32*cos(25.56)\\W=46 J

4 0
3 years ago
A transmission diffraction grating with 420 lines/mm is used to study the light intensity of di event orders (n). A screen is lo
Goshia [24]

Answer:

Explanation:

Diffraction grating is used to form interference pattern of dark and bright band.

Distance between adjacent slits (a ) = 1 / 420 mm

= 2.38 x 10⁻³ mm

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= 680 x 10⁻⁹ m

For bright red band

position x on the screen

= n λD / a ,         n = 0,1,2,3 etc

D = distance of screen

putting n = 1 , 2 and 3 , we can get three locations of bright red band.

x₁ = λD / a

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= .8 m

= 80 cm

Position of second bright band

= 2 λD / a

= 2 x 80

= 160 cm

Position of third bright band

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Answer:

gravity

Explanation:

7 0
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Answer:

24.3 m/s

Explanation:

1 kmh = 0.27 m/s, that makes a conversion ratio of 0.27/1kmh

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The "kmh" n the top and bottom cancel out. And  then you just multiply the top 90 x 0.27 and the bottom 1 x 1 to get

\frac{24.3 m/s}{1}

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