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Ilya [14]
3 years ago
9

When Maggie applies the brakes of her car, the car slows uniformly from 15.3 m/s to 0 m/s in 2.23 s. How far ahead of a stop sig

n must she apply her brakes in order to stop at the sign? Answer in units of m
Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

The answer is 34.119m

Explanation:

You need to pay attention to the word "uniformly". It means there is no acceleration thus the physics of this problem respond to the uniform rectilinear motion equations:

  • Xf = Xo + vt
  • v = constant
  • a = 0

where:

  • Xf = Final position
  • Xo = Origin position
  • v = velocity (speed)
  • t = time
  • a = acceleration

Xf = 0 + (15.3)(2.23)

Xf = 34.119m

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VladimirAG [237]

That's what happens if there is more than one force acting on the
object, and the forces are balanced, that is, they all "cancel out".

Think of the rope in a Tug-'o-War.  It has 50 musclebound football guys
all pulling the rope to the west, and 150 strong cheerleaders all pulling
the rope to the east.  The total force to the west is exactly equal to the
total force to the east, and the rope doesn't move at all.  The forces on it
are balanced, and the effect on its motion is the same as if there were  
no force on it at all.


7 0
2 years ago
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1050 kg and was approaching at
Soloha48 [4]

Answer:

v = 11.0 m/s at 198.6° (18.6° south of west)

ΔKE = -145 kJ

Explanation:

I assume you want to find the final velocity and the change in kinetic energy.

Take east to be +x and north to be +y.

Momentum is conserved in the x direction:

(1050 kg) (0 m/s) + (750 kg) (-25.0 m/s) = (1050 kg + 750 kg) vₓ

vₓ = -10.4 m/s

Momentum is conserved in the y direction:

(1050 kg) (-6.00 m/s) + (750 kg) (0 m/s) = (1050 kg + 750 kg) vᵧ

vᵧ = -3.50 m/s

The magnitude of the final velocity is:

v² = (-10.4 m/s)² + (-3.50 m/s)²

v = 11.0 m/s

The direction of the final velocity is:

θ = atan(-3.50 m/s / -10.4 m/s)

θ = 198.6°

The initial kinetic energy is:

KE₀ = ½ (1050 kg) (6.00 m/s)² + ½ (750 kg) (25.0 m/s)²

KE₀ = 253,275 J

The final kinetic energy is:

KE = ½ (1800 kg) (11.0 m/s)²

KE = 108,682 J

The change in kinetic energy is:

ΔKE = 108,682 J − 253,275 J

ΔKE ≈ -145,000 J

7 0
3 years ago
Scientists might model the water cycle by using a diagram. What are two
natta225 [31]

Answer: A and B

Explanation: it says benefits and the other two are not benefits.

5 0
3 years ago
What is the role of the neutral wire
lions [1.4K]

Answer:

The neutral wire is often confused with ground wire, but in reality, they serve two distinct purposes. Neutral wires carry currents back to power source to better control and regulate voltage. Its overall purpose is to serve as a path to return energy.

5 0
2 years ago
In the standing waves experiment, the string has a mass of 31.2 g and a length of 0.7 m. The string is connected to a mechanical
mestny [16]

Answer:

linear density of the string = 4.46 × 10⁻⁴ kg/m

Explanation:

given,

mass of the string = 31.2 g

length of string = 0.7 m

linear density of the string = \dfrac{mass\ of\ string}{length}

linear density of the string = \dfrac{31.2\times 10^{-3}\ kg}{0.7\ m}

linear density of the string = 44.57 × 10⁻³ kg/m

linear density of the string = 4.46 × 10⁻⁴ kg/m

7 0
3 years ago
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