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Anna71 [15]
3 years ago
12

IF A CAR AHEAD OF YOU HAS STOPPED AT A CROSSWALK, YOU SHOULD:

Engineering
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

well, depend if theres a stop sign or a light signal..you can always just honk at him/her so they proceed

Explanation:

but otherwise, the answer would be

A: stop and proceed when safe

<em><u></u></em>

<em><u>Hope this helped! Have a nice day, and feel free to follow me on insta (leo_g_rios)</u></em>

<em><u>-XxDeathshotxX</u></em>

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In this problem set, you will implement multidimensional scaling (MDS) from scratch. You may use standard matrix/vector librarie
EleoNora [17]

Features of Multidimensional scaling(MDS) from scratch is described below.

Explanation:

Multidimensional scaling (MDS) is a way to reduce the dimensionality of data to visualize it.  We basically want to project our (likely highly dimensional) data into a lower dimensional space and preserve the distances between points.  

If we have some highly complex data that we project into some lower N dimensions, we will assign each point from our data a coordinate in this lower dimensional space, and the idea is that these N dimensional coordinates are ordered based on their ability to capture variance in the data.  Since we can only visualize things in 2D, this is why it is common to assess your MDS based on plotting the first and second dimension of the output.  

If you look at the output of an MDS algorithm, which will be points in 2D or 3D space, the distances represent similarity. So very close points = very similar, and points farther away from one another = less similar.

Working of MDS

The input to the MDS algorithm is our proximity matrix.  There are  two kinds of classical MDS that we could use:  Classical (metric) MDS is for data that has metric properties, like actual distances from a map or calculated from a vector .Nonmetric MDS is for more ordinal data (such as human-provided similarity ratings) for which we can say a 1 is more similar than a 2, but there is no defined (metric) distance between the values of 1 and 2.

Uses

Multidimensional scaling (MDS) is a means of visualizing the level of similarity of individual cases of a dataset. MDS is used to translate "information about the pairwise 'distances' among a set of n objects or individuals" into a configuration of n points mapped into an abstract Cartesian space.

8 0
3 years ago
Alternating current flows in___ direction(s) and direct current flows in___direction(s)
Oduvanchick [21]

Answer:

<u><em>both, one</em></u>

Explanation:

<em>Alternating current flows in both directions and direct current flows in one  direction.</em>

<em></em>

<em>Hope it helps.</em>

<em>;)</em>

<em><3</em>

8 0
3 years ago
EJERCICIO 6
Ket [755]

Answer:

mnfokfnfi3or

Explanation:

can you translate it into english.....

8 0
3 years ago
The acceleration due to gravity on the surface of the moon is 1.62m/s^2. The moon's radius is Rm+1738km. A) What is the weight i
Anastaziya [24]

Answer:

weight is 12.6 N

force is 4.05 N

Explanation:

given data

acceleration = 1.62 m/s²

radius = 1738 km

mass = 10 kg

distance = 1738 km

to find out

weight and force

solution

we apply here weight formula that is

weight =  mass × acceleration    ...................1

put here value

weight =  10 × 1.26

weight = 12.6 N

and

force = mass × An

force = 10 × 1.62 (1738/ 1738+1738)² = 4.05 N

so force is 4.05 N

4 0
3 years ago
Copper spheres of 20-mm diameter are quenched by being dropped into a tank of water that is maintained at 280 K . The spheres ma
Ivenika [448]

Answer:

The height of the water is 1.25 m

Explanation:

copper properties are:

Kc=385 W/mK

D=20x10^-3 m

gc=8960 kg/m^3

Cp=385 J/kg*K

R=10x10^-3 m

Water properties at 280 K

pw=1000 kg/m^3

Kw=0.582

v=0.1247x10^-6 m^2/s

The drag force is:

F_{D} =\frac{1}{2} Co*p_{w} A*V^{2}

The bouyancy force is:

F_{B} =V*p_{w} *g

The weight is:

W=V*p_{c} *g

Laminar flow:

v_{T} =\frac{p_{c}-p_{w}*g*D^{2}   }{18*u} =\frac{(8960-1000)*9.8*(20x10^{-3})^{2}  }{18*0.00143} =1213.48 m/s

Reynold number:

Re=\frac{1000*1213.48*20x10^{-3} }{0.00143} \\Re>>1

Not flow region

For Newton flow region:

v_{T} =1.75\sqrt{(\frac{p_{c}-p_{w}  }{p_{w} })gD }=1.75\sqrt{(\frac{8960-1000}{1000} )*9.8*20x10^{-3} }  =2.186m/s

Re=\frac{1000*2.186*20x10^{-3} }{0.00143} =30573.4

Pr=\frac{\frac{u}{p} }{\frac{K}{pC_{p} } } =\frac{u*C_{p} }{k} =\frac{0.0014394198}{0.582} =10.31

Nu=2+(0.4Re^{1/2} +0.06Re^{2/3} )Pr^{2/5} (u/us)^{1/4} \\Nu=2+(0.4*30573.4^{1/2}+0.06*30573.4^{2/3}  )*10.31^{2/5} *(0.00143/0.00032)^{1/4} \\Nu=476.99

Nu=\frac{h*d}{K_{w} } \\h=\frac{476.99*0.582}{20x10^{-3} } =13880.44W/m^{2} K

\frac{T-T_{c} }{T_{w}-T_{c}  } =e^{-t/T} \\T=\frac{m_{c}C_{p}  }{hA_{c} } =\frac{8960*10x10^{-3}*385 }{13880.44*3} =0.828 s

e^{-t/0.828} =\frac{320-280}{360-280} \\t=0.573\\heightofthewater=2.186*0.573=1.25m

8 0
3 years ago
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