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lina2011 [118]
3 years ago
11

Which structure is located between the auricle and the eardrum? O stirrup O ear canal O auditory nerve Ocochlea​

Chemistry
1 answer:
Damm [24]3 years ago
3 0

Answer:

The structure that is located between the auricle and the eardrum is the ear canal.

Explanation:

The ear canal, or external ear canal, is a a tubular hole about 30 mm long that runs from the auricle to the eardrum, forming part of the external ear.

Its function is to conduct sound, in the form of vibrations, from the outside to the eardrum. It also has the function of producing a viscous secretion called cerumen, capable of trapping dust particles and small foreign bodies.

Other options are not correct because:

  • <em>Stirrup is located in the middle ear, along with the anvil and hammer. </em>
  • <em>Cochlea is in the inner ear and continues with the auditory nerve.</em>

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A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
Leni [432]

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

<em>The reaction is endothermic</em>

<em />

As the reaction is endothermic, when the reaction occurs,

<em>the heat is absorbed.</em>

<em></em>

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

<h3>3.06x10¹kJ are absorbed</h3>
8 0
3 years ago
In what specific situations would you use a light microscope? an electron<br>microscope?​
galina1969 [7]

ANSWER

A standard light microscope is used to view living organisms with little contrast to distinguish them from the background, which would be harder to see with the electron microscope.

Electron microscopes can be used to examine not just whole cells, but also the subcellular structures and compartments within them.

7 0
3 years ago
Epsom salt is commonly purchased in the pharmacy for a variety of uses, anti-inflammatory, laxative, and cosmetic. epsom salt is
Dominik [7]
Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.

Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x

By proportion, 
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980

Answer: there are 7 water of hydration in Epsom salt, according to the experiment.

Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses.  However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
4 0
3 years ago
Read 2 more answers
State boyl"s law and Charle's law​
zubka84 [21]

Answer:

hey mateee

Boyle's law :-  the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

Boyle's law can also be formularized as P1V1 = P2V2

Charle's law :-  the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

Charle's law can also be formularized as V1/T1 = V2/T2  

6 0
3 years ago
During complete oxidation of the fatty acid CH3(CH2)14COOH, ________ molecules of acetyl-CoA are produced, and the fatty acid go
zimovet [89]

Answer:

During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.

Explanation:

In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..

The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.

The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.

6 0
3 years ago
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