Answer is: 4) The same subscripts are on each side of the equation.
For example, balanced chemical reaction:
2Mg + O₂ → 2MgO.
1) The same number of atoms is on each side of the equation: two magnesium atoms and two oxgen atoms.
2) The formulas for all substances are correct: in magnesium oxide (MgO), magnesium has oxidation number +2 and oxygen -2, so formula is good, because compound must be neutral.
3) The same mass is represented on each side of the equation: because there is same number of atoms, the mass is the same.
4) The same subscripts are on each side of the equation: oxygen does not have same subscripts.
If solutions of nh4cl(aq) and nh3(aq) are mixed, the ions in the resulting solution that would be the spectator ions in any acid-base chemistry occurring in the solution would be the chloride ions. The mixture is a common buffer of ammonia and ammonium chloride. NH4Cl is a salt that is soluble in water dissociating into NH4+ and Cl-. The chloride ions are the spectator ions while NH4+ ions would be the conjugate acid for the buffer solution. Buffer solutions are solution which would resist change in pH when acid or a base is being added to the solution. The equilibrium reaction of the buffer solution in this problem would be
NH3 + H2O = OH– + NH4+
Respuesta:
Yes.
Explicación:
Las teorías se pueden mejorar o modificar a medida que se recopila más información para que la precisión de la predicción sea mayor con el tiempo.
<span>Kr> Br> As> Se> Ge> Ca> Ga > K </span>
Answer:
ΔS = 16.569 J/K
Explanation:
In this case, we need to use the correct expression to solve this. In thermodynamics, the expression to use that puts a relation between heat, temperature and entropy is the following:
ΔS = Q/T
To determine the entropy change of the universe, we need to sum the entropy change of Earth and the entropy of the sun.
As the sun is transfering radiation to Earth, the sun is losing energy, therefore, heat is negative, while Earth receives the heat, so it's positive. Calculating the entropy for the sun and Earth:
ΔSs = -Q/Ts
ΔSe = Q/Te
ΔSu = ΔSe + ΔSs
Let's calculate both entropies by separate:
ΔSe = 5x10^3 / 285 = 17.54 J/K
ΔSs = -5x10^3 / 5,150 = -0.971 J/K
Therefore, the entropy of universe:
ΔSu = 17.54 - 0.971
ΔSu = 16.569 J/K
