Answer:
As the phase changes occur, the freedom of motion of the particles increases
Explanation:
As the phase changes occur from solid to gas, the freedom of motion of the particles increases
At the solid state (let's say ice), the molecules of the solid are tightly packed and they are unable to move freely. When heat is applied to the state of the solid, ice it melts and the molecules of the solid gains kinetic energy and therefore tends to shift away from their mean fixed position due to heat. This kinetic energy possesses by this molecules allow them to move freely (energy due to motion). When further heat is applied to the liquid (above the boiling point), the molecules of the water vapourizes(turns to gas) and this molecules gain more kinetic energy more than they do in liquid state and were able to move freely more than in liquid. This shows that the freedom of the particles (molecules) increase with change in state from solid to gas.
Power:
P= A/t
A = F · h = m · g · h
P = m · g · h / t, m = 7.5 kg, g = 9.81 m/s², h = 8.2 m, t = 1800 s
P = 7.5 · 9.81 · 8.2 / 1800 = 0.335 W
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Answer:
More the mass, greater the inertia
So the greatest inertia will be possessed by C. 10 lb bag of potatoes
Hope this helps!
Answer:
Part A: D
Part B: W = Qh - Qc
Part C: e = 1 - Qc/Qh
Explanation:
The heat engine is the engine that transforms heat (Q) in work (W), and by the second law of the thermodynamics, its efficiency can not be 100%, it means that some heat must be dissipated.
Part A:
The engine works with two sources of heat, one hot (Qh) at a hot temperature (Th) and another cold (Qc) at a cold temperature (Tc). It is necessary so, the hot source will give energy to the fluid of the engine, and the cold source will be the source where these heat will dissipate and the fluid will return to its original temperature. So,
Qh > Qc, and Th > Tc
Part B:
The ideal heat engine is the one that can use the most amount of heat to transform it at work. It is characterized by Qh/Qc = Th/Tc.
The work is the useful energy, so it is the total heat (Qh) less the heat dissipated (Qc):
W = Qh - Qc
Part C:
The effiency is the useful energy divided by the total energy. Because W = Qh - Qc:
e = W/Qh
e = (Qh - Qc)/Qh
e = Qh/Qh - Qc/Qh
e = 1 - Qc/Qh