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Nimfa-mama [501]
3 years ago
7

Classify each of these reactions. A single reaction may fit more than one classification. Ba ( ClO 3 ) 2 ⟶ BaCl 2 + 3 O 2 Ba(ClO

3)2⟶BaCl2+3O2 double‑displacement (a.k.a. exchange or metathesis) combination (synthesis) displacement decomposition redox NaNO 2 + HCl ⟶ NaCl + HNO 2 NaNO2+HCl⟶NaCl+HNO2 decomposition displacement combination (synthesis) redox double‑displacement (a.k.a. exchange or metathesis) CaO + CO 2 ⟶ CaCO 3 CaO+CO2⟶CaCO3 double‑displacement (a.k.a. exchange or metathesis) displacement decomposition redox combination (synthesis) ZnSO 4 + Mg ⟶ Zn + MgSO 4 ZnSO4+Mg⟶Zn+MgSO4 double‑displacement (a.k.a. exchange or metathesis) displacement decomposition combination (synthesis) redox
Chemistry
1 answer:
Vilka [71]3 years ago
4 0

Answer: a) Ba(ClO_3)_2\rightarrow BaCl_2+3O_2:  Decomposition

b) NaNO_2+HCl\rightarrow NaCl+HNO_2: double displacement

c) CaO+CO_2\rightarrow CaCO_3: Synthesis (Combination)

d) ZnSO_4+Mg\rightarrow MgSO_4+Zn: redox

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Ba(ClO_3)_2\rightarrow BaCl_2+3O_2

A double displacement reaction is one in which exchange of ions take place.

NaNO_2+HCl\rightarrow NaCl+HNO_2

Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

CaO+CO_2\rightarrow CaCO_3

Redox reaction is a type of chemical reaction in which oxidation and reduction takes place in one single reaction. The oxidation number of one element increases and the oxidation number of other element decreases.

ZnSO_4+Mg\rightarrow MgSO_4+Zn

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3 years ago
g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
Liono4ka [1.6K]

Answer:

<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

  • Volume, V = 304 mL = 0.304 liter
  • Molarity, M = 0.36 M
  • number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
  • 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

<u>2. LIthium hydroxide, LiOH</u>

  • Volume, V = 341 mL = 0.341 liter
  • Molarity, M = 0.51 M
  • number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
  • 1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

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Answer:

<u>Solubility of the liquid increases with temperature.</u>

Explanation:

The solubility of the liquid increases with increase in the temperature but there is no effect of the pressure on the solubility of a liquid, whereas, the solubility of gases in liquids increases on increasing the pressure above above the surface of the liquid.

On increasing temperature of a liquid solvent the kinetic energy of the particles of the solvent increases which makes particles to move faster which breaks the particles of the solute more rapidly with more energy.

Also the saturation point of a solvent can be increased by increasing the temperature of it which allows to dissolve more solute in the solvent beyond the saturation point.

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