Answer:
Partial pressure of hydrogen H₂ = 0.32 atm
Explanation:
Given:
Total pressure = 0.48 atm
Find:
Partial pressure of hydrogen
Computation:
Number of mole of H₂ = 1 / 2 = 0.5 moles
Number of mole of He = 1 / 4 = 0.25 moles
Total moles = 0.5 + 0.25 = 0.75
Partial pressure of hydrogen H₂ = [moles / total moles] Total pressure
Partial pressure of hydrogen H₂ = [0.50 / 0.75]0.48 atm
Partial pressure of hydrogen H₂ = 0.32 atm
If the difference in electronegativtiy for the atoms in a bond are greater than 0.4,we consider the bond polar, if the electronegativity is less than 0.4, we consider it non polar. if there are no polar bonds, the molecule is non polar.
<h2>Let us study about boiling point </h2>
Explanation:
Boiling point
It is the temperature at which liquid changes into gaseous state .
or it can be defined as :
the temperature at which the vapor pressure of a liquid becomes equals to atmospheric pressure .
It depends upon many factors :
- Temperature
- Pressure
- Inter molecular forces present
- Environmental pressure or vapor pressure
Temperature : more is the temperature , more is the vapor pressure hence more is the boiling point .
Pressure : More is the pressure , ore is the boiling point or vice versa .
Intermolecular forces in particles of matter : more are the forces , less is the boiling point as they will have no escaping tendency .
The boiling point of water is : 100 degree celsius
Hey there!
Molar mass of O3 = 47.9982 g/mol
therefore:
1 mole O₃ --------------------- 47.9982 g
moles O₃ ---------------------- 24 g
moles O₃ = 24 x 1 / 47.9982
moles O₃ = 24 / 47.9982
moles O₃ = 0.500 moles
Hope this helps!