Answer:
it is easy use the formula of triangle which is 1/2(base × height) and base is the side where the height touches and height means the perpendicular line.
And in some cases there may be the use of pythagoras theorem
Answer:
1.3
Friend is wrong
Step-by-step explanation:
Given:
friend's claim: height of his building is more than 1.50 times the height of yours
line of sight to the top edge of the other building makes an angle of 21° above the horizontal
line of sight to the base of the other building makes an angle of 52° below the horizontal
Solution:
Let A be the height of your building is A
Let B+A his building is B higher than yours.
Let the distance between the buildings is x.
then
tan 52 = A/x
tan 21 = B/x
A/B = tan 52 / tan 21
= 1.27994 / 0.38386
A/B = 3.33
(A + B) / A = 1.5
0
A/A + B/A = 1.50
1 + B/A = 1.50
B/A is basically (B/x) / (A/x)
So
1+ 3.33 / 3.33
= 4.33/3.33
= 1.3
Since 1.3 is not equal to 1.5
Hence the friend's claim is wrong.
Answer:
4 and 2
Step-by-step explanation:
- <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>
- <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>
According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>
<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse