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valentina_108 [34]
3 years ago
15

What is the name of the part of the expressway where cars can both enter and exit?

Engineering
1 answer:
True [87]3 years ago
4 0

Answer:

interchange

Explanation:

interchange is the intersection of two highways

at different levels with separate connecting roads for the transfer of traffic from one highway to the other through a series of ramps. The connecting ramps allow drivers to leave the road and enter another safely, without impeding the flow of traffic.

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Provide three examples of things engineers can implement when designing environmentally sustainable projects.
Dafna1 [17]
Water supply.
Food production.
Housing and shelter.
Sanitation and waste management.
Energy development.
Transportation.
6 0
3 years ago
Read 2 more answers
Consider a mixing tank with a volume of 4 m3. Glycerinflows into a mixing tank through pipe A with an average velocity of 6 m/s,
Svetach [21]

This question is incomplete, the complete question as well as the missing diagram is uploaded below;

Consider a mixing tank with a volume of 4 m³. Glycerin flows into a mixing tank through pipe A with an average velocity of 6 m/s, and oil flow into the tank through pipe B at 3 m/s. Determine the average density of the mixture that flows out through the pipe at C. Assume uniform mixing of the fluids occurs within the 4 m³ tank.

Take p_o = 880 kg/m³ and p_{glycerol = 1260 kg/m³    

 

Answer:

the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³  

Explanation:

Given that;

Inlet velocity of Glycerin, V_A = 6 m/s

Inlet velocity of oil, V_B = 3 m/s  

Density velocity of glycerin, p_{glycerol = 1260 kg/m³

Density velocity of glycerin, Take p_o = 880 kg/m³

Volume of tank V = 4 m

from the diagram;

Diameter of glycerin pipe, d_A = 100 mm = 0.1 m

Diameter of oil pipe, d_B = 80 mm = 0.08 m

Diameter of outlet pipe d_C = 120 mm = 0.12 m

Now, Appling the discharge flow equation;

Q_A + Q_B = Q_C

A_Av_A + A_Bv_B = A_Cv_C

π/4 × (d_A)²v_A + π/4 × (d_B )²v_B = π/4 × (d_C)²v_C

we substitute

π/4 × (0.1 )² × 6 + π/4 × (0.08 )² × 3 = π/4 × (0.12)²v_C

0.04712 + 0.0150796 = 0.0113097v_C

0.0621996 = 0.0113097v_C

v_C = 0.0621996 / 0.0113097

v_C  = 5.5 m/s

Now we apply the mass flow rate condition

m_A + m_B = m_C

p_{glycerin}A_Av_A + p_0A_Bv_B = pA_Cv_C  

so we substitute

1260 × π/4 × (0.1 )² × 6 + 880 × π/4 × (0.08 )² × 3 = p × π/4 × (0.12)² × 5.5

1260 × 0.04712 + 880 × 0.0150796 = p × 0.06220335

59.3712 + 13.27 = 0.06220335p  

72.6412 = 0.06220335p    

p = 72.6412 / 0.06220335

p =  1167.8 kg/m³  

Therefore, the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³  

4 0
3 years ago
Air from a workspace enters the air conditioner unit at 30°C dry bulb and 25°C wet bulb temperatures. The air leaves the air con
PSYCHO15rus [73]

Answer:

See explaination

Explanation:

The volume flow rate Q Q QQ of a fluid is defined to be the volume of fluid that is passing through a given cross sectional area per unit time.

Kindly check attachment for the step by step solution of the given problem.

4 0
3 years ago
A plastic molding machine produces a product whose annual demand is in the millions.
BabaBlast [244]

Answer:

a. 78.4 pieces/hr

b. $0.1806/min

c. $1.34/piece

Explanation:

(a) With a cycle time Tc = 45 sec = 0.75 min.

Production rate, Rp = 60/0.75 = 80 pieces/hr.

Let us factor in the 98% proportion uptime, so Production rate, Rp = 0.98*(80) = 78.4 pieces/hr

Quantity of product annualy = 6000 *(78.4) = 470,400 pieces/yr

(b) Equipment cost rate, Ceq = 500,000(1.30)/(60 x 10 x 6000) = $0.1806/min.

(c) Cost per piece of mould, Ct = 100,000/1,000,000 = $0.10/piece

Cost rate of labour ,CL = 18.00(0.20) = $3.60/hr = $0.06/min

Conclusively, cost per piece, Cpc = 1.20(0.88) + (0.06 + 0.1806)(0.75) + 0.10 = $1.34/piece

8 0
3 years ago
Respiratory protection ____________________________ against fumes and gases.
anygoal [31]

Respiratory protection <u>provides fool proof protection</u> against fumes and gases during wielding.

<h3>What is PPE?</h3>

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which is designed and developed to offer protection to different parts of the body while working in a potentially hazardous environment.

Some examples of personal protective equipment (PPE) that are used to protect the different parts of the body include the following:

  • Respirators
  • Face mask
  • Face shield
  • Gloves
  • Boots
  • Helmet

In conclusion, respiratory protection <u>provides fool proof protection</u> against fumes and gases during wielding.

Read more on PPE here: brainly.com/question/19131588

#SPJ1

3 0
1 year ago
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