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2 years ago

What is the name of the part of the expressway where cars can both enter and exit?

Engineering

1 answer:

True [87]2 years ago

4 0

Answer:

interchange

Explanation:

interchange is the intersection of two highways

at different levels with separate connecting roads for the transfer of traffic from one highway to the other through a series of ramps. The connecting ramps allow drivers to leave the road and enter another safely, without impeding the flow of traffic.

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10% A steel beam W18x76 spans 32 feet and is subjected to a Moment of 334 kips-ft. Find the load w on the beam. Determine the de

Lilit [14]

Answer:

w = 10.437 kips

deflection at 1/4 span 20.83\E ft

at mid span = 1.23\E ft

shear stress 7.3629 psi

Explanation:

area of cross section = 18*76

length of span = 32 ft

moment = 334 kips-ft

we know that

moment = load *eccentricity

334 = w * 32

w = 10.437 kips

deflection at 1/4 span

$\delta = \frac{wa^2b^2}{3EI}$

$= \frac{10.4375*8^2 *24^2}{3E \frac{BD^3}{12}}$

$=\frac{10.437 *8^2*24^2}{3E \frac{18*16^3}{12}}$

= 20.83\E ft

at mid span

$\delta = \frac{wl^3}{48EI}$

$= \frac{10.43 *32^3}{48 *E*\frac{18*16^3}{12}}$

$\delta = 1.23\E ft$

shear stress

$\tau = \frac{w}{A} = \frac{10.43 7*10^3}{18*76} =7.3629 psi$

6 0

3 years ago

True or False: Galvanized steel pipe can withstand moderate freezing.

yaroslaw [1]

Answer:

True

Explanation:

Older galvanized steel pipes, which have a tendency to freeze, are a bit more forgiving and will likely not burst. They can withstand extreme cold and warm temperatures.

5 0

2 years ago

An overhead 25m-long, uninsulated industrial steam pipe of 100-mm diameter, is routed through a building whose walls and air are

wariber [46]

Answer:

1) q=18414.93 W

2) C=12920$

Explanation:

Given data:

pipe length L=25m

pipe diameter D=100mm =0.1 m

air temperature $T_{s1}$ = $T_{\infty1} }$ =25 °C.....= 298.15k

pipe surface temp $T_{s2}$ =150 °C.....=423.15k

surface emissivity e= 0.8

boiler efficiency η=0.90

natural gas price Cg=$0.02 per MJ

1) Total heat loss and radiation heat loss combined

q= $q_{conv} +q_{rad}$

q= $A[h(T_{s2}-T_{s1})+e$ б( $T_{s2}$ ^4- $T_{s1}$ ^4)]....... (1)

б=5.67×10^-8 W/m^2K^4 (boltzmann constant)

area A =L.Dπ=25×0.1π=7.85 m^2

putting all these values in eq (1)

q=18414.93 W

2) suppose boiler is operating non stop annual energy loss will be

E=q.t

=18414.93.3600.24.365

=5.81×10^11 J

to find furnace energy consumption

Ef =E/η

=6.46×10^5 MJ

annual cost

C=Cg. Ef

=12920$

8 0

2 years ago

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are

jek_recluse [69]

In a slowly cooled hypereutectoid iron-carbon steel, the pearlite colonies are normally separated from each other by a more or less continuous boundary layer of cementite done by Slower cooling reasons coarse Pearlite, even as rapid cooling reasons first-rate pearlite to form.

<h3>What levels is in Hypereutectoid metal?</h3>

Hypoeutectoid steels can, upon preliminary cooling from the austenite single segment field, exist as extraordinary levels, eutectoid ferrite and austenite, every with extraordinary carbon contents.

At room temperature, hypereutectoid steels have a pearlitic primary microstructure (ferrite grains with embedded cementite lamellae) with moreover induced cementite on the grain boundaries! The micrograph under suggests a hypereutectoid metal with 1.0 Carbon (C100).