You and Mae are in free-float frames. Mae has just passed you, traveling at a speed of 60 km/hr. You throw a ball toward her at
1 answer:
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Answer:
See below
Explanation:
280 km east then 190 km north
Use Pythagorean theorem to find the resultant displacement
d^2 = 280^2 + 190^2
d = 338.4 km
Angle will be arctan ( 190/280) = 34.16 °
Explanation:
Given that,
A ball is tossed straight up with an initial speed of 30 m/s
We need to find the height it will go and the time it takes in the air.
At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :
v = u +at
Here, a = -g
v = u -gt
i.e. u = gt
So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds
Let d is the maximum distance covered by it.
Putting all values
Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.
Answer:
Their translational kinetic energies are the same
Explanation:
The translational kinetic energy of an object is given by the formula:
Where m = the mass of the object and
v = the linear speed of the object
From the question, it is stated that wheel A has the same mass as wheel B, that is
Linear speed is also a function of the distance covered. Since both wheels cover the same distance within the same interval, we can conclude that
Both wheels A and B have equal speed and mass, this means that their translational kinetic energy is the same.
Note that translational kinetic energy is not a function of the radius