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Katen [24]
2 years ago
8

Sulfuric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that sulfuric acid can under

go when it's dissolved in water.
Chemistry
1 answer:
Dmitriy789 [7]2 years ago
4 0

Answer:

H₂SO₄ (aq) + H₂O (l)  → HSO₄⁻ (aq) + H₃O⁺ (aq)

HSO₄⁻ (aq) + H₂O (l) ⇄  SO₄⁻²(aq) + H₃O⁺ (aq)           Ka

Explanation:

The sulfuric acid is a dyprotic acid.

It is a considered a strong acid but only the first deprotonation is strong.

Second deprotonation is totally weak

That's why we have equilibrium when it release the second proton.

Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium

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An atom has 19 protons and 20 neutrons. what is the atomic number with steps​
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39

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What are two ways in which density has practical importance?
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6 0
3 years ago
If 0.500 mol of each of the following solutes is dissolved in 2.0 L of water, which will cause the greatest increase in the boil
serious [3.7K]

Answer is: D. Na2SO4.

b(solution) = 0.500 mol ÷ 2.0 L.

b(solution) = 0.250 mol/L.

b(solution) = 0.250 m; molality of the solutions.

ΔT = Kf · b(solution) · i.

Kf - the freezing point depression constant.

i - Van 't Hoff factor.

Dissociation of sodium sulfate in water: Na₂SO₄(aq) → 2Na⁺(aq) + SO₄²⁻(aq).

Sodium sulfate dissociates on sodium cations and sulfate anion, sodium sulfate has approximately i = 3.

Sodium chloride (NaCl) and potassium iodide (KI) have Van 't Hoff factor approximately i = 2.

Carbon dioxide (CO₂) has covalent bonds (i = 1, do not dissociate on ions).

Because molality and the freezing point depression constant are constant, greatest freezing point lowering is solution with highest Van 't Hoff factor.

8 0
3 years ago
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please hurry! If 3.87g of powdered aluminum oxide is placed in a container containing 5.67g of water, what is the limiting react
VikaD [51]

Answer:

Explanation:

Given parameters:

Mass of aluminium oxide = 3.87g

Mass of water = 5.67g

Unknown:

Limiting reactant = ?

Solution:

The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.

Using the number of moles, we can ascertain the limiting reactants;

         Al₂O₃  + 3H₂O  →  2Al(OH)₃  

Number of moles;

            Number of moles = \frac{mass}{molar mass}

molar mass of Al₂O₃  = (2x27) + 3(16) = 102g/mole

    number of moles = \frac{3.87}{102}  = 0.04mole

   

molar mass of  H₂O = 2(1) + 16 = 18g/mole

    number of moles = \frac{5.67}{18}  = 0.32mole

From the reaction equation;

        1 mole of  Al₂O₃  reacted with 3 moles of H₂O

   0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O

But we were given 0.32 mole of H₂O and this is in excess of amount required.

This shows that Al₂O₃ is the limiting reactant

           

6 0
2 years ago
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