At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3 At this temp, 0.3000 mol of H2 and 0.300 mol o

Question

andreev551 [17]

4 years ago

10

At a certain temperature, the equilibrium constant, Kc, for this reaction is 53.3 At this temp, 0.3000 mol of H2 and 0.300 mol o

f I2 were placed in a 1L container to react. What concentration of HI is present at equilibrium? H2+I2<-> 2HI

Chemistry

1 answer:

Vlada [557] · Answer 1 · 2021-12-26T15:51:48+03:00

Vlada [557]4 years ago

4 0

Your answer is: Kc = [HI]² / {[H2] [I2]}
53.3 = (2x)² / {(0.400M - x)(0.400M - x)} 
sqrt(53.3) = 2x / (0.400M - x) 
2.92 - 7.30x = 2x 
x = 0.314M 

[HI] = 2x = 0.628M

:) hopefully this helped. (: