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wlad13 [49]
3 years ago
11

A 2.50-l sample of a colorless gas at stp decomposed to give 2.50 l of n2 and 1.25 l of o2 at stp. what is the colorless gas?

Chemistry
3 answers:
damaskus [11]3 years ago
8 0

Answer;

N2O (Nitrogen (i) oxide.

Explanation;

The decomposition would be; 2N2O(g) = 2N2 (g)+ O2 (g)

Which means the ratio of; N2O :N2 :O2 = 2:2:1

The volume of colorless gas is 2.5 liters, N2 is 2.5 liters and oxygen is 1.25 liters; which also gives us a ratio of; 2: 2: 1.

Alternatively; here is twice as much N2 as O2. therefore; the formula would be N2O (nitrogen dioxide) to make 1 volume of N2 for every 2 volumes of O2.

Schach [20]3 years ago
4 0

Answer;

N2O (Nitrogen (i) oxide.

Explanation;

The decomposition would be; 2N2O(g) = 2N2 (g)+ O2 (g)

Which means the ratio of; N2O :N2 :O2 = 2:2:1

The volume of colorless gas is 2.5 liters, N2 is 2.5 liters and oxygen is 1.25 liters; which also gives us a ratio of; 2: 2: 1.

Alternatively; here is twice as much N2 as O2. therefore; the formula would be N2O (nitrogen dioxide) to make 1 volume of N2 for every 2 volumes of O2.

leonid [27]3 years ago
4 0

Answer;

N2O (Nitrogen (i) oxide.

Explanation;

The decomposition would be; 2N2O(g) = 2N2 (g)+ O2 (g)

Which means the ratio of; N2O :N2 :O2 = 2:2:1

The volume of colorless gas is 2.5 liters, N2 is 2.5 liters and oxygen is 1.25 liters; which also gives us a ratio of; 2: 2: 1.

Alternatively; here is twice as much N2 as O2. therefore; the formula would be N2O (nitrogen dioxide) to make 1 volume of N2 for every 2 volumes of O2.

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#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

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=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

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