Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
Answer:.633
Explanation:
I have know idea but it was right
Explanation:
Answer: 12CO2(g) +12H2O(l)->C12H24O12(s)+12O2(g)
Once you make balancing equations don't disturb the given numbers because it is fix you need to solve by the side of the chemical name.
Explanation:
1: fluorine to form lithium fluoride
2:bcos covalent bond exists btw two non metals
3: bcos it is d combination of two or more elements nd elements r substances
4: for sbustances we hv flame test nd splint test
ionic compounds are held by strong electrostatic forces of attraction
The rate of reaction is always expressed in concentration per time like mol/L·s. The equation is:
r [mol/L·s] = kCⁿ, where n is the order of reaction. Since k is 1300/s, that means that Cⁿ = C such that (1/s)*(mol/L) = mol/L·s. Thus, n=1. For a first order reaction, the formula would be:
ln(A/A₀) = -kt
where
A is the amount of material after time t
A₀ is the amount of material at t=0
The half life is when A/A₀ = 1/2÷1 = 1/2. Thus, the half-life t is:
ln(1/2) = (-1300t)
t = 5.33×10⁻⁴ seconds
