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Marina CMI [18]
3 years ago
15

Which best describes the oxidizing agent in this reaction? Cl2(aq) + 2Br(aq) 2Cl(aq) + Br2(aq) Bromine (Br) is the oxidizing age

nt because it gains an electron. Bromine (Br) is the oxidizing agent because it loses an electron. Chlorine (Cl) is the oxidizing agent because it gains an electron. Chlorine (Cl) is the oxidizing agent because it loses an electron
Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0
Answer:
            <span>Chlorine (Cl) is the oxidizing agent because it gains an electron.

Explanation:
                   Reaction is as follow,

</span><span>                     Cl</span>₂<span> (aq)  +  2 Br</span>⁻<span> (aq)    </span>→   <span> 2Cl(aq)  +  Br</span>₂ <span>(aq)

Oxidation Reaction:

                                    2 Br</span>⁻     →     Br₂  +  2 e⁻

Two atoms of Br⁻ (Bromide) looses two electrons to form Br₂ molecule. Hence it is oxidized and is acting as reducing agent.

Reduction Reaction:

                                   Cl₂  +  2 e⁻    →     2 Cl⁻

One molecule of Cl₂ gains two electrons to form two chloride ions (Cl⁻). Therefore, it is reduced and has oxidized Br⁻, Hence, acting as a oxidizing agent.
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LenKa [72]

Answer:

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Explanation:

3 0
3 years ago
What is the mass in grams of 2.6 moles of angelic acid?
Dennis_Churaev [7]

Answer:

260.34g

Explanation:

First, you need to know what angelic acid is comprised of. It is written as C₅H₈O₂.

In order to solve for the mass of 2.6 moles of angelic acid, you need the mass of 1 mole of angelic acid. This can be found by adding the masses from the periodic table, like shown below:

5 carbon atoms = (5)(12.01g) = 60.05g

8 hydrogen atoms = (8)(1.01) = 8.08g

2 oxygen atoms = (2)(16) = 32g

angelic acid = 60.05 + 8.08 + 32 = 100.13g

Then, set up a basic stoichiometric equation and solve. The units should cancel out.

(\frac{2.6mol}{1} )(\frac{100.13g}{1mol} )=260.34g

5 0
2 years ago
Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



5 0
3 years ago
describe how a pure dry sample of solid lead carbonate can be obtained from sodium carbonate solution and lead nitrate solution
djyliett [7]

Answer:

Soluble salts can be made by reacting acids with soluble or insoluble reactants. Titration must be used if the reactants are soluble. Insoluble salts are made by precipitation reactions.

Making insoluble salts

An insoluble salt can be prepared by reacting two suitable solutions together to form a precipitate.

Determining suitable solutions

All nitrates and all sodium salts are soluble. This means a given precipitate XY can be produced by mixing together solutions of:

X nitrate

sodium Y

For example, to prepare a precipitate of calcium carbonate:

X = calcium and Y = carbonate

mix calcium nitrate solution and sodium carbonate solution together

calcium nitrate + sodium carbonate → sodium nitrate + calcium carbonate

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3(aq) + CaCO3(s)

It also works if potassium carbonate solution or ammonium carbonate solution is used instead of sodium carbonate solution. Remember that all common potassium and ammonium salts are soluble.

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Explanation:

7 0
2 years ago
I need help with this one
Kruka [31]

Answer:

H, B, G, D, E, C, A, F

explanation: the ones that are the deepest are the oldest

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