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timofeeve [1]
3 years ago
6

Which statement about fusion is correct? Fusion creates radioactive waste. Fusion is the combining of small nuclei under extreme

heat and pressure. Fusion is the splitting of atoms under extreme heat and pressure. Fusion is the splitting of a nucleus when it is bombarded by neutrons. NextReset
Chemistry
2 answers:
nataly862011 [7]3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

Fusion is a nuclear process in which two or more atomic nuclei combine together to form a bigger atomic nuclei.

Thus, the statement fusion is the combining of small nuclei under extreme heat and pressure is correct.

During this process large amount of heat is released.

For example,  the energy of sun is due to the fusion processes occurring inside it.

Goshia [24]3 years ago
6 0

Answer choice 'B' is correct.

#PlatoFam

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Round off the following measurement to three significant figures. 1.296 g
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It would be 1 or 2 because if the number is higher than 5 you need to round up , if its lower than 5 you need to round down.

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What element is 1s2 2s22p6 3s23p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f10
skad [1K]
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Bi (Bismuth)
4 0
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Read 2 more answers
What volume of water vapor would be produced from the combustion of 815.74 grams of propane (C3H8) with 1,006.29 grams of oxygen
d1i1m1o1n [39]

3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane (C_3H_8) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Stoichiometric calculations:

C_3H_8(g) + 5 O_2(g)→ 3 CO_2(g) + 4 H_2O(g)

From the equation of the reaction, the mole ratio of propane to oxygen is 1:5.

Mole of 815.74 grams of propane = \frac{ 815.74}{44.1 }

Mole of 815.74 grams of propane = 18.49750567 moles

Mole of  1,006.29 grams of oxygen =\frac{ 1,006.29}{32 }

Mole of  1,006.29 grams of oxygen = 31.4465625 moles

Going by the mole ratio, it appears propane is limiting while oxygen is in excess.

From the equation, 1 mole of propane produces 4 moles of water vapour. Thus, the equivalent mole of water vapour will be:

18.49750567 moles x 4 = 73.99 moles.

Using the ideal gas equation:

PV = nRT

v = (73.99  x 0.08206 x 623) ÷ 0.96

v =  3940.2

Hence, 3940.2 is the volume of water vapour that would be produced from the combustion of 815.74 grams of propane (C_3H_8) with 1,006.29 grams of oxygen gas, under a pressure of 1.05 atm and a temperature of 350. degrees C.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

7 0
2 years ago
Choose the correct answer from the choices below
marusya05 [52]

Answer:

either h or j

Explanation:

3 0
2 years ago
A container is filled with oxygen gas, and the pressure of
Amanda [17]

Answer:

77,007 Pa

Explanation:

Hello!

In this case, since the equivalence statement for atmospheres and pascals is:

1 atm = 101,325 Pa

We can set up the following conversion factor to obtain the pressure in pascals:

0.760atm*\frac{101,325Pa}{1atm}\\\\=77,007Pa

Best regards!

3 0
2 years ago
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