33) In the power plant based on nuclear energy

What happens to sound waves from an object as it moves toward you?

Olegator [25]

The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

<h3>What is sound waves?</h3>

Sound waves refer to a form of transverse wave that compress and vibrate while travelling from one medium to another thereby transferring energy.

Therefore, The event that happens to sound waves from an object as it moves toward you is The pitch gets higher because of an increase in wavelength.

Learn more about sound waves below.

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4 0

2 years ago

A 25 Kg rock is sitting on a cliff that is 50 meters above the ground. If it fell off of the cliff, and all energy was conserved

svetlana [45]

Answer:

v = 31.32 [m/s]

Explanation:

To solve this problem we must use the principle of energy conservation, which tells us that potential energy is converted into kinetic energy or vice versa. The potential energy can be calculated by the product of mass by gravity by height.

$E_{pot}=m*g*h$

where:

Epot = potential energy [J]

m = mass = 25 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

$E_{pot}=25*9.81*50\\E_{pot}= 12262.5[J]$

When the rock falls the potential energy is converted into kinetic energy.

$E_{pot}=E_{k}\\E_{k}=\frac{1}{2}*m*v^{2}$

where:

Ek = kinetic energy [J]

v = velocity [m/s]

Now clearing v:

$v^{2} =\frac{E_{k}*2}{m}\\v=\sqrt{(2*12262)/25}\\v = 31.32 [m/s]$

8 0

3 years ago

Objects with masses of 235 kg and a 535 kg are separated by 0.330 m. (a) find the net gravitational force exerted by these objec

saul85 [17]

The 61.0 kg object ... F = (300kg)(6.673×10−11 N m^2 kg^−2)(61kg)/(.225m)^2. F = 2.412e-5 N towards the 495 kg block. b. [195kg] ===.45m ... (b) You cannot achieve this position. For the net force to become zero, one or both of the masses must ...

7 0

3 years ago

A piston–cylinder assembly fitted with a slowly rotating paddle wheel contains 0.13 kg of air, initially at 300 K. The air under

olganol [36]

Answer:

Explanation:

From the first law of thermodynamics

Q=ΔU+W

Q=heat supplies to the system

ΔU=change in internal energy of the system

W= work done by the gas by the system

Q =12 KJ