Answer:
Molarity of solution is 1.10x10⁻³ M
Explanation:
Solute NaOCl
7.4% by mass means, that in 100 grams of solution, we have 7.4 g of solute.
Molar mass of NaOCl = 74.45 g/m
Mol = Mass / Molar mass
7.4 g / 74.45 g/m = 0.099 moles
Density of solution = 1.12 g/mL
Density = Mass / volume
1.12g/mL = 100 g / volume
Volume = 100 g / 1.12g/mL = 89.3 mL
Molarity = mol /L
89.3 mL = 0.0893 L
0.099 moles / 0.0893 L = 1.10x10⁻³ M
The enthalpy for the reaction : ΔH = -132
<h3>Further explanation</h3>
Given
Reaction and the enthalpy
Required
the enthalpy
Solution
Hess Law
Reaction 1 reverse :
A + B = G + C ΔH = -277
Reactions 2 and 3 remain the same (unchanged)
C + F = A ΔH = 303
D = B + H ΔH = -158
Add up all the reactions and remove the same compound from two different sides
D + F = G + H ΔH = -132
<span>PV=nRT= a universal constant
For any condition
P1V1/n1T1=R
and
P2V2/n2T2=R
i.e
P1V1/n1T1=P2V2/n2T2
Becomes
V1/n1=V2/n2
rearranging and solving
V2=V1X(n2/n1)= 750 mLx((0.65+0.35)/(0.65))=1200ml=1.2L...2 sig figs</span>
Answer:
2
Explanation:
In balancing nuclear reactions the mass number and atomic numbers are usually conserved. This implies that from the given equation, the sum of the number of the subscript on the right hand side must be equal to that on the left hand side. This also applies to the superscript:
For the mass numbers(superscript):
235 + 1 = 1 + 139 + 95
236 = 235
This is not balanced
For the atomic number:
92 + 0 = 0 + 53 + 39
92 = 92
This is balanced.
We simply inspect to see how to balance the mass number.
By putting a coefficient of 2 behind the neutron atom, the equation becomes balanced.
Moles of Ammonia produced : 4 moles
<h3>Further explanation</h3>
Given
6 mol of H₂
Required
moles of Ammonia
Solution
Reaction
N₂ + 3H₂ → 2NH₃
In chemical equations, the reaction coefficient shows the mole ratio of the reacting compound (reactants and products)
From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so mol NH₃ :
= 2/3 x moles H₂
= 2/3 x 6
= 4 moles
