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Ira Lisetskai [31]
3 years ago
8

When attempting a Grignard reaction, you add the correct molar amount of acetone but what you didn’t know was that your lab part

ner also added an equimolar amount of 2,4-dimethylpentan-3-one. You used 1-bromohexane to generate the Grignard reagent and the reaction proceeded. What two products would you likely obtain (IUPAC nomenclature)? Should be products be in an equal ratio? Why or why not?
Chemistry
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

The products formed are

2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol

The products should be in equal ratio since an equipmolar amount of acetone and 2,4-dimethylpentan-3-one was initially present as reactants

Explanation:

Ketones reacts with gridnard reagents to form tertiary alcohol, and since acetone and 2,4-dimethylpentan-3-one are both ketones, gridnard reagent reduced both to tertiary alcohols:2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol

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A)The lower the greenhouse gases, the higher the ocean temperature.
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6 0
2 years ago
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Ideal He gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. During this proce
kkurt [141]

Explanation:

The given data is as follows.

             P = 3 atm

                = 3 atm \times \frac{1.01325 \times 10^{5} Pa}{1 atm}  

                 = 3.03975 \times 10^{5} Pa

    V_{1} = 9 L = 9 \times 10^{-3} m^{3}    (as 1 L = 0.001 m^{3}),  

        V_{2} = 15 L = 15 \times 10^{-3} m^{3}

            Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

                  W = P \times \Delta V

or,                W = P \times (V_{2} - V_{1})

Therefore, putting the given values into the above formula as follows.

                  W = P \times (V_{2} - V_{1})

                      = 3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})

                      = 1823.85 Nm

or,                   = 1823.85 J

As internal energy of the gas \Delta E is as follows.

                     \Delta E = Q - W

                                  = 800 J - 1823.85 J

                                  = -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.

8 0
3 years ago
One of the reasons that stars are so large is because _____.
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Answer:

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4 0
3 years ago
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How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
Anna [14]

Answer:

12 moles of F₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

Xmol of F₂ = (3 × 8)/2

Xmol of F₂ = 12 moles

Thus, 12 moles of F₂ is needed for the reaction.

8 0
2 years ago
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