When attempting a Grignard reaction, you add the correct molar amount of acetone but what you didn’t know was that your lab part
ner also added an equimolar amount of 2,4-dimethylpentan-3-one. You used 1-bromohexane to generate the Grignard reagent and the reaction proceeded. What two products would you likely obtain (IUPAC nomenclature)? Should be products be in an equal ratio? Why or why not?
2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol
The products should be in equal ratio since an equipmolar amount of acetone and 2,4-dimethylpentan-3-one was initially present as reactants
Explanation:
Ketones reacts with gridnard reagents to form tertiary alcohol, and since acetone and 2,4-dimethylpentan-3-one are both ketones, gridnard reagent reduced both to tertiary alcohols:2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol
Because the amount of element Zn reaction is equal the production. Also as the amount of Hydrogen and Chloride in the reaction and the production are equal.
<span>To solve this we assume that the gas inside the balloon is an ideal </span>gas. Then, we can use the ideal gas equation which is
expressed as PV = nRT. At a constant volume pressure and number of moles of the gas
the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:
