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Ksju [112]
3 years ago
8

ON a meter stick, one centimeter is generally the___ a)length of the whole stick b)length of the one hundred sticks c)distance b

etween two of the numbered lines d)distance between two of the small, unnumbered lines NEED HELP ASAP
Chemistry
1 answer:
Elena-2011 [213]3 years ago
7 0

c)distance between two of the numbered lines

Explanation:

On a meter stick, a centimeter is usually the distance between two of the numbered lines. A meter stick is a device for measuring the length of an object.

  • A hundred centimeters makes up a meter and this is the number of divisions on a meter stick.
  • Each distance between numbered vertical lines is a centimeter apart.
  • On a meter stick that is 1m long, there are 100cm.

Learn more:

lengths brainly.com/question/4687435

#learnwithBrainly

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An objects tendency to maintain its current state of motion is called
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Inertia is the tendency of an object to remain at rest or remain in motion. Inertia is related to an object's mass.
3 0
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Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li(s) + N2(g) → 2Li3N(s) How many moles of lit
miss Akunina [59]

Answer:

12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N

Explanation:

The reaction is:

6Li(s) + N₂(g) → 2Li₃N(s)

If nitrogen is in excess, the lithium is the limiting reactant.

Ratio is 2:6

2 moles of nitride were produced by 6 moles of Li

Then, 0.6 moles of nitride were produced by (0.6 .6)/ 2 = 1.8 moles of Li

Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li

7 0
3 years ago
Read 2 more answers
Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )
Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol

b) To calculate the constant we have the following expression:

lnK=-\frac{deltaG_{rxn} }{RT}

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066

c) The equilibrium pressure of O₂ over M is:

K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm

3 0
3 years ago
The measured value 24.00 g has an uncertainty of?
Orlov [11]

Answer:

±0.005 g

Explanation:

The uncertainty depends on whether the measurement was obtained manually or digitally.

1. Manual

The minimum uncertainty is ±0.01 g.

It may be greater, depending on random or personal errors

2. Digital

Most measurements of mass are now made on digital scales.

A digital device must always round off the measurement it displays.

For example, if the display reads 20.00, the measurement must be between 20.005 and 19.995 (±0.005).

If the measured value were 20.006, the display would round up to 20.01.

If the measured value were 19.994, the display would round down to 19.99.

The uncertainty is ±0.005 g.

The scale shown below would display a mass of 20.00 g

6 0
3 years ago
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