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sergij07 [2.7K]
3 years ago
15

During an all-night cram session, a student heats up a 0.577 liter (0.577 x 10- 3 m3) glass (pyrex) beaker of cold coffee. initi

ally, the temperature is 15.8 °c, and the beaker is filled to the brim. a short time later when the student returns, the temperature has risen to 91.3 °c. the coefficient of volume expansion of coffee is the same as that of water. how much coffee (in cubic meters) has spilled out of the beaker
Physics
1 answer:
krok68 [10]3 years ago
5 0

Here coffee is filled into a glass cup and when it is heated expansion of coffee as well as glass occurs

we will find the change in volume of glass cup and change in the volume of coffee.

volume expansion is calculated by

\Delta V = V_o \gamma \Delta T

for pyrex glass we have

\gamma = 4 * 10^{-6}

now by the formula

\Delta V = 4* 10^{-6} * 0.577 * (91.3 - 15.8)

\Delta V = 0.174 mL

Now for the expansion of coffee

\gamma = 2.14 * 10^{-4}

now the expansion of coffee will be

\Delta V = 2.14 * 10^{-4}* 0.577* (91.3 - 15.8)

\Delta V = 9.32 mL

now the coffee that will spill out of the cup will be

\Delta V = 9.32 mL - 0.174 mL

\Delta V = 9.15 mL

so 9.15 mL coffee will spill out of the cup

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ValentinkaMS [17]

M = mass of aluminium = 1.11 kg

c_{a} = specific heat of aluminium = 900

T_{ai} = initial temperature of aluminium = 78.3 c

m = mass of water = 0.210 kg

c_{w} = specific heat of water = 4186

T_{wi} = initial temperature of water = 15 c

T = final equilibrium temperature = ?

using conservation of heat

Heat lost by aluminium = heat gained by water

M c_{a} (T_{ai} - T) = m c_{w} (T - T_{wi} )

(1.11) (900) (78.3 - T) = (0.210) (4186) (T - 15)

T = 48.7 c

7 0
3 years ago
The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves pa
tensa zangetsu [6.8K]

Complete question:

Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Part B: What is the momentum of a proton traveling at 0.62 c ?

Answer

a)Who would have aged less=The Captain would have aged less

b) p=3.96*10^{-19}kgm/s

Explanation:

From the question we are told that

Length measured by captain l_c=50m

Speed of rocket past tje space dock V=0.5c

Length measured by space-dock personnel l_c=43.3m

a)

Generally time moves slower when moving at speed of light, due to time dilation or variation.

Who would have aged less=The Captain would have aged less

b)

Generally the equation for Relativistic Momentum  is mathematically given as

p=\frac{m*v}{1 - v^2/c^2}

p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}

p=3.96*10^{-19}kgm/s

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3 years ago
A dog running at 10 m/s is 30m behind a rabbit moving at 5 m/s. when will the dog catch up with the rabbit assuming both their v
dedylja [7]

The will dog catch up with the rabbit in 6 minutes assuming both their velocities remain constant during the chase.

<h3>What time will the dog catch the rabbit?</h3>

The time that the dog will catch up with the rabbit is given as follows:

Let the distance covered by the rabbit be x.

Distance covered by dog = x + 30

  • Time taken = distance/speed

The time taken will be the same T

  1. Time taken by dog, T = (x + 30)/10
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Equating both times.

(x + 30)/10 = x/5

x = 30 m

Solving for T in equation (ii);

T = 30/5 = 6 minutes

In conclusion, time is obtained as a ratio of distance and speed.


Learn more about time and speed at: brainly.com/question/26046491

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Mars2501 [29]

Answer:

yes

Explanation:

yes

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A hiker walked a hiking trail according to the chart below. What is a possible explanation of the hiker's movement?
joja [24]
<span>a.The hiker had an easy, level trail from 11:00-12:00 and was able to travel the fastest during that time period.---> may be because this was indeed fastest  stage


b.The hiker got tired and walked the slowest from 1:00-2:00.---> no, because this was not the slowest stage


c.The hiker stopped for lunch from 11:00-12:00 and that slowed him down.---> no because this was the fastest stage


d.The hiker ended up in the same place that he started.---> no, because the hiker walked more toward east than toward west and more toward south than toward north.

Answer: option a)
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