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notsponge [240]
3 years ago
8

Good butters. Norman Good and his colleagues developed a series of compounds that are useful buffers near neutral pH. Three of t

hese buffers are abbreviated MES (pK2 = 6.15), MOPS |(pK= 7.15), and HEPPS (8.00). (a) Which of these buffers would be most effective near pH 7.0? (b) Near 6.0?
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

(a) MOPS

(b) MES

Explanation:

Buffers are solutions whose function is to resist drastic changes in pH when an <em>acid</em> or a <em>base</em> is added. They are formed by 2 components:

  • A weak acid and its conjugate base (e.g., HF/F⁻).               <u>(acid buffer)</u>
  • A weak base and its conjugate acid (e.g., NH₃/NH₄⁺).      <u>(basic buffer)</u>

pH and be pOH can be calculated, in each case, according to Henderson-Hasselbalch equations:

pH = pKa + log ([conjugate base]/[weak acid])           <u>(acid buffer)</u>

pOH = pKb + log ([conjugate acid]/[weak base])        <u>(basic buffer)</u>

It is possible to see that when the concentration of acid is equal to that of its base, pH = pKa or pOH = pKb. This is the point where the buffer has its optimum performance. Nevertheless, it has its most effective range of work (buffer range) when the ratio acid:base is between 0.1 and 10. If we take these values into Henderson-Hasselbalch equations, we can see that the optimum range of work is:

  • For acid buffer, pH = pKa ± 1
  • For basic buffer, pOH = pKb ± 1

In (a) (pH = 7.0), the solution is closet to the pK of the MOPS buffer, so this would be the best choice. Nevertheless, both MES and HEPPS would be suitable options, because their buffer ranges comprise pH = 7.0.

In (b) (pH = 6.0), the solution is closest to the pK of the MES buffer, so this would be the best option. Other buffers are not suitable because pH = 6.0 is out of their buffer range.

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One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su
Tpy6a [65]

Answer : The percent purity of Fe_2O_3 in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

Fe_2O3+3CO\rightarrow 2Fe+3CO_2

First we have to calculate the mass of Fe.

\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}

Molar mass of Fe = 55.8 g/mole

\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole

Now we have to calculate the moles of Fe_2O_3

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of Fe_2O_3

So, 3.15\times 10^4mole of Fe produced from \frac{3.15\times 10^4}{2}=15750 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3

Molar mass of Fe_2O_3 = 159.69 g/mole

\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg

Now we have to calculate the percent purity of Fe_2O_3 in the original sample.

Mass of original sample = 2.86\times 10^3kg

\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100

\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%

Therefore, the percent purity of Fe_2O_3 in the original sample is 87.94 %

3 0
3 years ago
Which notations represent hydrogen isotopes?
lisabon 2012 [21]

Isotopes are chemical elements with same atomic number (Z), but different mass number (different number of neutrons).

Hydrogen is an element with atomic number 1. It has three isotopes:

1) protium (₁¹H), with mass number 1 (no neutrons).

2) deuterium (₁²H), with mass number 2 (one neutrons, n° = 2 -1, n° = 1).

3) tritium (₁³H), with mass number 3 (two neutrons, n° = 3 -1, n° = 2).

3 0
3 years ago
Read 2 more answers
Give the ground-state electron configuration for each of the following elements. After each atom is its atomic number in parenth
Anni [7]

Answer:

(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

(b) ₁₀Ne: 1s² 2s² 2p⁶

---

(a) 3

(b) 6

(c) 7

Explanation:

We can state the ground-state electron configuration for each element following Aufbau's principle.

(a) ₁₉K: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

(b) ₁₀Ne: 1s² 2s² 2p⁶

Second part

(a) Al belongs to Group 13 in the Periodic Table. It has 13-10=3 electrons in the valence shell.

(b) O belongs to Group 16 in the Periodic Table. It has 16-10=6 electrons in the valence shell.

(c) F belongs to Group 17 in the Periodic Table. It has 17-10=7 electrons in the valence shell.

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3 years ago
A. How many hydrogen atoms are on the Reactants side?
patriot [66]
The reactants side are the first ones in a chemical reaction. 
8 0
3 years ago
I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
olya-2409 [2.1K]
Hope this helps message me if you need help understanding it

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