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Scrat [10]
3 years ago
9

Hehe

Physics
1 answer:
Harman [31]3 years ago
3 0

Answer:

i would be ur friend

Explanation:

You might be interested in
A 12.0N force with a fixed orientation does work on a
kvasek [131]

Answer:

(a) \theta=62.31^{\circ}

(b) \theta=117.68^{\circ}

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, d=(2.00i -4.00j+3.00k)\ m

Magnitude of displacement, d=\sqrt{2^2+4^2+3^2}= 5.38\ m

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

W=Fd\ cos\theta

\theta is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

cos\theta=\dfrac{W}{Fd}

cos\theta=\dfrac{+30\ J}{12\times 5.38}

\theta=62.31^{\circ}

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

cos\theta=\dfrac{W}{Fd}

cos\theta=\dfrac{-30\ J}{12\times 5.38}

\theta=117.68^{\circ}

Hence, this is the required solution.

8 0
3 years ago
An object of height 2.7 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 12
kati45 [8]

Answer:

A)  q = -8.488 cm ,  B)  m = 0.29

Explanation:

A) For this exercise in geometric optics, we will use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} +  \frac{1}{q}

where p and q are the distance to the object and image, respectively and f is the focal length

in our case the distance the object is p = 29 cm the focal length of a diverging lens is negative and indicates that it is f = - 12 cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

     

we calculate

          \frac{1}{q} = - \frac{1}{12} - \frac{1}{29}

          \frac{1}{q} = - 0.1178

          q = -8.488 cm

the negative sign indicates that the image is virtual

B) the magnification is given

          m = \frac{h'}{h} = - \frac{q}{p}

       

we substitute

          m = - \frac{-8.488}{29}

          m = 0.29

the positive sign indicates that the image is right

4 0
3 years ago
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
gizmo_the_mogwai [7]

Answer:reactant,active site,enzyme below,substrate,products

Explanation:

5 0
3 years ago
A pencil is rolled off a table of height 0.92 m. If it has horizontal speed pf 1.4 m/s, how long does it take the pencil to reac
Alenkasestr [34]

The distance an object falls, from rest, in gravity is

                         D  =  (1/2) (G) (T²)

                        'T' is the number seconds it falls.

In this problem,

                         0.92 meter = (1/2) (9.8) (T²)

Divide each side by  4.9 :   0.92 / 4.9 = T²

Take the square root
of each side:                          √(0.92/4.9) = T

                                                  0.433 sec = T    

The horizontal speed doesn't make a bit of difference in
how long it takes to reach the floor.  BUT ... if you want to
know how far from the table the pencil lands, you can find
that with the horizontal speed.

The pencil is in the air for  0.433 second.
In that time, it travels
                                   (0.433s) x (1.4 m/s) = 0.606 meter

from the edge of the table.
 
3 0
3 years ago
Helppp pls yes or no question
svp [43]

Answer:

yes, should be

Explanation:

This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.

7 0
2 years ago
Read 2 more answers
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