The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem. For oxygen, the charge is 2-, the total considering its number of atoms is -24. Mn has a charge of +3. TO compute for Mn, we must achieve zero charge overall hence 3+3x-24=0 where x is the Cl charge. Cl charge, x is +7.
you can google it and it pops up right away
B is the.answer for this problem
Hello the answer is c love
5 g is bigger than 43 mg.
I hope this is right, I apologize if I'm wrong.
