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3 years ago

if the separation distance between the moon and the planet is increased by a factor of 4 then the force gravitational is

Physics

2 answers:

erastova [34]3 years ago

8 0

Answer:

Fg = (G * m1 * m2) / r^2

The gravitational force is Fg/16

Explanation:

Fg = (G * m1 * m2) / (4r)^2

Fg = (G * m1 * m2) / 16r

Therefore,

Fg / 16

cestrela7 [59]3 years ago

8 0

Answer:

1/16 th of the previous gravitational force

Explanation:

F =G (m1 x m2)/ r^2

r= distance between moon and planet

if r1 = 1 and r2= 4 1^2 / 4^2= 1/16

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10 hertz Hertz is the frequency of oscillation which is the number of oscillations per second. So if something takes 0.10 s per oscillation, divide 1 second by the period to get the frequency. So 1 / 0.10s = 10 1/s = 10 Hertz Therefore the object is vibrating at 10 hertz.

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3 years ago

A centrifuge rotor (hollow disk) is rotating at 10,000 rpm is shut off and brought to rest by a constant frictional torque of 1.

Y_Kistochka [10]

Answer:

The no of revolutions rotor turn before coming to rest is 1,601.1943 and time taken is equal to 19.21 seconds

Explanation:

here we know that torque = I×α

α= angular acceleration

I = moment of inertia of hollow disc = m× $k^{2}$

given that m=4.37kg

k=0.0710m

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$w_{o}=10000\times \frac{\pi}{30} rad /s$

$\alpha =\frac{torque}{I}$

from the above equation we can calculate the angular acceleration of the hollow disc .

since $w^{2}-w_o^{2} =2\alpha$ $\theta$

from this above equation $\theta=\frac{w^{2}-w_{o}^{2}}{2\alpha }$

no of revolutions = $\frac{\theta}{2\pi}$ = 1,601.1943.

Now to calculate time we know that time = $\frac{2\theta}{w+w_{o}}$

so upon calculating we will be getting t=19.21 seconds

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3 years ago

Electromagnetic waves do require a medium to travel. True False

pshichka [43]

Answer:

The Answer is false

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

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