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gulaghasi [49]
3 years ago
9

Why is my 2002 dodge caravan 3.3 liter disabling my electric components?

Physics
1 answer:
VARVARA [1.3K]3 years ago
8 0
Alright guys I’m back sorry for being gone but I had to deal with stuff in my life like school and I had to do a lot of things at once so I didn’t have time to get on but I am officially now back!
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8. Differentiate between each of these land designations made during the Progressive Era:
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A string is wound around a uniform disc of radius 0.68 m and mass 3.7 kg. The disc is released from rest with the string vertica
Zolol [24]

Answer:

3.962

Explanation:

mass = 1.2

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velocity = ?

mgh = 1/2mv² + 1/2(1/2)mv²

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What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w
Delvig [45]
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }=    10.2 Hz

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
f_n = n f_1
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz

c) Similarly, the third lowest frequency (third harmonic) is given by
f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz

8 0
3 years ago
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