Red shift of distant galaxies
Answer:
Oooo someone is writing a answer. (Also im new to this so Idk what to really do.)
Explanation:
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Explanation:
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Answer:
3.962
Explanation:
mass = 1.2
gravity g = 9.81
velocity = ?
mgh = 1/2mv² + 1/2(1/2)mv²
= 9.81 x 1.2 = 3/4v²
11.772 x 4 = 3/4v²
47.088 = 3v²
divide through both sides by 3
15.696 = v²
take the square root of both sides
√15.696 = √v²
= 3.6962 = v
the speed is therefore 3.692
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by

where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is

b) The frequency of the nth-harmonic for a standing wave in a wire is given by

where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:

c) Similarly, the third lowest frequency (third harmonic) is given by