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sukhopar [10]
3 years ago
11

In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 3.42 x 104-m length of wire

was let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of 6.80 x 103 m/s, and the magnitude of the earth's magnetic field at the location of the wire was 6.56 x 10-5 T. If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire
Physics
1 answer:
makvit [3.9K]3 years ago
8 0

Answer:

15116.4 V

Explanation:

B = Earth's magnetic field at the location = 6.5\times 10^{-5}\ T

L = Length of the wire = 3.42\times 10^4\ m

v = Velocity of the shuttle = 6.8\times 10^8\ m/s

The emf generated is given by

E=BLv\\\Rightarrow E=6.5\times 10^{-5}\times 3.42\times 10^{4}\times 6.8\times 10^3\\\Rightarrow E=15116.4\ V

The motional emf generated between the ends of the wire is 15116.4 V

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A 1300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/s in precisely oppositedirections participate in a head-on crash.
miskamm [114]

Given

Car 1

m1 = 1300 kg

v1 = 20 m/s

m2 = 900 kg

v2 = -15 m/s

(Negative sign shows that direction of car 2 is opposite to car 1)

Procedure

As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,

\begin{gathered} m_1v_1+m_2v_2=(m_1+m_2)v \\ v=\frac{m_1v_1+m_2v_2}{m_1+m_2} \\ v=\frac{1300\operatorname{kg}\cdot20m/s-900\operatorname{kg}\cdot15m/s}{1300\operatorname{kg}+900\operatorname{kg}} \\ v=5.681m/s \end{gathered}

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5 0
1 year ago
an object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object
emmainna [20.7K]

Answer:

The acceleration of the object is -30\ m/s^2

Explanation:

Given:

Initial velocity of object v_i = 200 feet/second

Final velocity of object v_f = 50 feet/second

Time of travel = 5 seconds

To calculate acceleration of the object we will find the rate of change of velocity with respect to time.

So, acceleration a is given by:

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Plugging in values to evaluate acceleration.

a=\frac{50-200}{5}

a=\frac{-150}{5}

a=-30\ m/s^2

The acceleration of the object is -30\ m/s^2 (Answer). The negative sign shows the object is slowing down.

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