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sukhopar [10]
3 years ago
11

In 1996, NASA performed an experiment called the Tethered Satellite experiment. In this experiment a 3.42 x 104-m length of wire

was let out by the space shuttle Atlantis to generate a motional emf. The shuttle had an orbital speed of 6.80 x 103 m/s, and the magnitude of the earth's magnetic field at the location of the wire was 6.56 x 10-5 T. If the wire had moved perpendicular to the earth's magnetic field, what would have been the motional emf generated between the ends of the wire
Physics
1 answer:
makvit [3.9K]3 years ago
8 0

Answer:

15116.4 V

Explanation:

B = Earth's magnetic field at the location = 6.5\times 10^{-5}\ T

L = Length of the wire = 3.42\times 10^4\ m

v = Velocity of the shuttle = 6.8\times 10^8\ m/s

The emf generated is given by

E=BLv\\\Rightarrow E=6.5\times 10^{-5}\times 3.42\times 10^{4}\times 6.8\times 10^3\\\Rightarrow E=15116.4\ V

The motional emf generated between the ends of the wire is 15116.4 V

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A proton initially moves left to right along the x-axis at a speed of 2.00 x 103 m/s. It moves into an uniform electric field, w
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Answer:

E = 1.04*10⁻¹ N/C

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