Answer:
The answer to your question is: T2 = 235.44 °K
Explanation:
Data
V1 = 3.15 L V2 = 2.78 L
P1 = 2.40 atm P2 = 1.97 atm
T1 = 325°K T2 = ?
Formula
![\frac{P1V1}{T1} = \frac{P2V2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1V1%7D%7BT1%7D%20%3D%20%5Cfrac%7BP2V2%7D%7BT2%7D)
Process
T2 = (P2V2T1) / (P1V1)
T2 = (1.97x 2.78x 325) / (2.40 x 3.15)
T2 = 1779.895 / 7.56
T2 = 235.44 °K
The answer is B: chronological order
Let MM(x) be the molar mass of x.
MM(Pb) : MM(PbO)
=207.21 : 223.20 = 451.4 g : x g
cross multiply and solve for x
x=223.2/207.21*451.4
= 486.23 g
Percentage yield = 365.0/486.23= 0.75067 = 75.07% (rounded to 4 sign. fig.)
What you have to do is balance the chemical equations to make sure everything is even on both sides. If you want me to help you answer the questions comment back