False,it could be false information like Wikipedia
Answer:
3 Hz
Explanation:
A beat is the pattern of interference among two waves with frequencies which are different.
The difference of the frequencies of the waves gives us the beat frequency.
Here, one frequency is
, the other frequency is 
So, the beat frequency

The beat frequency that is produced is 3 Hz
Answer:
a) 230 Km b) 76.7 km/h c) Please see below
Explanation:
a) If we can neglect the time while the driver accelerated, the movement can be divided in two parts, each of them at a constant speed:

⇒ 
b) The average x component of velocity, can be calculated applying the definition of average velocity, as follows:

If we choose t₀ = 0 and x₀ = 0, replacing xf and t by the values we have already found, we can find vavg,x as follows:

c) The found value of avg,x is not the same as the arithmetic average of the initial and final values of vx (70 Km/h) due to the time traveled at both velocities was not the same.
If the driver had droven half of the time (1.5 h) at 50 km/h and the other half at 90 km/h, total displacement would have been as follows:

Applying the definition of average velocity once more:

which is the same as the arithmetic average of the initial and final values of vₓ.
Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
![1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill]](https://tex.z-dn.net/?f=1%20%5Bkm%5D%20%3D%200.6214%20%5Bmill%5D%5C%5C45%5Bkm%5D%2A0.6212%5B%5Cfrac%7Bmill%7D%7B1km%7D%20%5D%3D27.95%20%5Bmill%5D)
Answer:
height is 69.68 m
Explanation:
given data
before it hits the ground = 46 % of entire distance
to find out
the height
solution
we know here acceleration and displacement that is
d = (0.5)gt² ..............1
here d is distance and g is acceleration and t is time
so when object falling it will be
h = 4.9 t² ....................2
and in 1st part of question
we have (100% - 46% ) = 54 %
so falling objects will be there
0.54 h = 4.9 (t-1)² ...................3
so
now we have 2 equation with unknown
we equate both equation
1st equation already solve for h
substitute h in the second equation and find t
0.54 × 4.9 t² = 4.9 (t-1)²
t = 0.576 s and 3.771 s
we use here 3.771 s because 0.576 s is useless displacement in the last second before it hits the ground is 46 % of the entire distance it falls
so take t = 3.771 s
then h from equation 2
h = 4.9 t²
h = 4.9 (3.771)²
h = 69.68 m
so height is 69.68 m