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gulaghasi [49]
3 years ago
12

Find the moment of inertia Ix of particle a with respect to the x axis (that is, if the x axis is the axis of rotation), the mom

ent of inertia Iy of particle a with respect to the y axis, and the moment of inertia Iz of particle a with respect to the z axis (the axis that passes through the origin perpendicular to both the x and y axes). Express your answers in terms of m and r separated by commas. Ix, Iy, Iz =
Physics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

Ix,Iy,Iz = mr²,9mr²,10mr²

Explanation:

The Question has some missing details.

To solve this question, I'll make the following assumptions.

Distance of particle x = r

Distance of particle y = 3r

Given

The mass of each particles = m

The moment of inertia is calculated by adding product of mass” of each particle with the “square of its distance from the axis of the rotation”.

Ix = m * (r)² = mr²

Iy = m(3r)² = m * 9r² = 9mr²

The distance of z from the axis is r² + (3r)²

So, Iz = m(r² + (3r)²)

Iz = m(r² + 9r²)

Iz = m(10r²)

Iz = 10mr²

So, we have

Ix,Iy,Iz = mr²,9mr²,10mr²

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A quantity of hot water at 91°C and another cold one at 12°C.
Burka [1]

Answer:

m_{cold}=567kg\\\\m_{hot}=233kg

Explanation:

Hello!

In this case, since equilibrium temperature problems involve the mass, specific heat and temperature change for the substances at different temperatures, we can write:

m_{cold}C_{cold}(T_{eq}-T_{cold})=-m_{hot}C_{hot}(T_{eq}-T_{hot})

Thus, since we are talking about water and they both have the same specific heat, we can write:

m_{cold}(T_{eq}-T_{cold})=-m_{hot}(T_{eq}-T_{hot})

Now, we plug in the temperatures to obtain:

m_{cold}(35-12)+m_{hot}(35-91)=0\\\\23m_{cold}-56m_{hot}=0

Next, since the total volume of water is 800 L, since it has a density of 1kg/L, we infer the total mass is 800 kg; that is why we can write a 2x2 system of simultaneous equations:

\left \{ {{23m_{cold}-56m_{hot}=0} \atop {m_{cold}+m_{hot}=800}} \right.

Thus, the masses of both cold and hot water turn out:

m_{cold}=567kg\\\\m_{hot}=233kg

Best regards!

7 0
3 years ago
What is the acceleration of this object? The object's mass is 60 kg.
slamgirl [31]
We know, F = m*a
Here, F = 600-400 = 200 N downwards 
m = 60 Kg

Substitute their values, 
a = 200/60
a = 20/6
a = 10/3
a = 3.33 m/s² downwards

In short, Your Answer would be 3.33 m/s² downwards

Hope this helps!
5 0
3 years ago
Read 2 more answers
The ______________of matter depends upon how close the individual particles are together.
Simora [160]
The state of matter depends upon how close the individual particles are together
3 0
3 years ago
by scale drawing, find the resultant of vectors 70N inclined at100N and direction of the resultant 100N​
Thepotemich [5.8K]

Answer: 70n=

<h3>at100n=</h3>

100n=

Explanation:

4 0
3 years ago
A Smart Car, which has a mass of 1000 kg, is going 20 m/s. When it hits the barrier, it stops with a time of 0.5 seconds. What i
antiseptic1488 [7]

Answer:

The change in momentum = -20000 kg m/s.

Explanation:

Mass m = 1000 kg

speed v₁ = 20 m/s

speed v₂ = 0 m/s

We know that,

The change in momentum

ΔP = m (Δv)

ΔP = m (v₂ - v₁)

     = 1000 (0 - 20)

     = 1000 (-20)

     = -20000 kg m/s

Thus, the change in momentum = -20000 kg m/s.

Note: negative sign indicates that the velocity is reducing when it hits the barrier.

4 0
3 years ago
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