Two opposite forces generate a force whose magnitude is the difference of the two magnitudes, and whose direction is the same of the strongest one.
We have 3320 newtons forward, and 550 backwards.
So, the net force is forward, and has magnitude ![3320-550=2770](https://tex.z-dn.net/?f=%203320-550%3D2770)
Answer:
True
Explanation:
The Florida law states that a person driving an animal-drawn vehicle has the same protections that are applicable to a person driving a vehicle and the protections that are applicable to pedestrians also apply to a person riding or leading an animal upon a roadway or the shoulder of it. According to this, the answer is that the statement is true.
The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be
C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by
![f=\frac{v_T}{4L}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv_T%7D%7B4L%7D)
where, ![v_T=v\sqrt{\frac{T}{273} }](https://tex.z-dn.net/?f=v_T%3Dv%5Csqrt%7B%5Cfrac%7BT%7D%7B273%7D%20%7D)
Since, T=37+273 K = 310 K
v = 331 m/s
![\therefore v_T=331\sqrt{\frac{310}{273} } = 352.72 \ m/s](https://tex.z-dn.net/?f=%5Ctherefore%20v_T%3D331%5Csqrt%7B%5Cfrac%7B310%7D%7B273%7D%20%7D%20%3D%20352.72%20%5C%20m%2Fs)
Using this, we get:
![f=\frac{352.72}{4(0.240)} \\f=367.42 \ Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B352.72%7D%7B4%280.240%29%7D%20%5C%5Cf%3D367.42%20%5C%20Hz)
Hence, the fundamental frequency is 367.42 Hz.
To learn more about Attention here:
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Answer:
Convection currents are the result of different heating. Lighter material (warm) rises while heavier (cold) material sinks. This movement of the materials is what causes convection currents! (BTW, it happens in water, in the atmosphere, and in the mantle of Earth!
Explanation:
I hope this helps a little! :)
1.5 m/s is the velocity.
9.3 m is the length of aisle, over which Distance will be covered.
Time is demanded in which the child will move the cart over the aisle with 1.5 m/s.
v=S/t
and,
t=S/v
Put values,
t=9.3/1.5=6.2 s