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Naya [18.7K]
3 years ago
14

A bicycle racer sprints near the end of a race to clinch a victory. The racer has an initial velocity of 12.1 m/s and accelerate

s at the rate of 0.350 m/s2 for 6.07 s. What is his final velocity?
Physics
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

v= 14.22 m/s

Explanation:

Given that

u = 12.1 m/s

a=0.35   m/s².

t= 6.07 s

We know v = u +at

v=final velocity

u=initial velocity

t=time

a=acceleration

Now by putting the values in the above equation

v= 12.1 + 0.35 x 6.07 m/s

v= 14.22 m/s

Therefore the final velocity will be 14.22 m/s.

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Answer:

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Explanation:

 From  the question we are that

       The mass of the particle m = 1.8*10^{-3} kg

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         F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \  ( 1.63 \r i  + 0.980 \r j )T)

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           i \ \ X \ \ j = k \\\\j \ \  X  \ \ k = i\\\\k  \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \  X  \ \ j = -i\\\\i  \ \ X \ \ k = - j\\

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        F = ma

Making a the subject

      a = \frac{F}{m}

   Substituting values

     a =\frac{(-5.966*10^4) \r k}{1.81*10^{-3}}

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