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Dennis_Churaev [7]
3 years ago
6

How do observing and inferring differ?

Physics
2 answers:
ddd [48]3 years ago
8 0
Observation = you are seeing it as in: I can physically see rain therefore it IS raining
Inference = making a point based on suggestions as in: there are puddles on the ground. It must be raining therefore it IS raining
Illusion [34]3 years ago
6 0
Observing is commenting on what you see e.g: It is raining.
Inferring is drawing conclusions from observations for example you see the road is wet so you might infer that it rained last night.
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Estimate the Joule-Thomson coefficient of refrigerant-134a at 0.70 MPa and 50°C. Assume the second state will be selected for a
leva [86]

Answer:

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

Explanation:

The Joule-Thomson coefficient is the ratio of the change of temperature to the change of pressure under isoenthalpic conditions:

\mu = \left(\frac{\Delta T}{\Delta P}\right)_{h}

Initial and final properties are:

T_{1} = 50^{\textdegree}C, P_{1}=700\,kPa, h_{1}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

T_{2} = 48.186^{\textdegree}C, P_{2}=600\,kPa, h_{2}=288.54\,\frac{kJ}{kg}. Superheated Vapor.

The Joule-Thomson coefficient is approximately:

\mu = \frac{50^{\textdegree}C-48.186^{\textdegree}C}{700\,kPa-600\,kPa}

\mu = 0.018\,\frac{^{\textdegree}C}{kPa}

5 0
4 years ago
Carbon bums in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?
diamong [38]

B. carbon + oxygen -- carbon dioxide

Explanation:

The best equation that describes a reaction where carbon combines by burning in the presence of oxygen to produce carbon dioxide is:

    carbon + oxygen -- carbon dioxide

Every chemical reaction is made up of reactants and products

Reactants are the species on the left hand side of an equation, the products are those on the right hand side.

The reactants combines chemically to give produces.

The kind of reaction depicted above is a synthesis or combination reaction where two species combines to gives a product or more;

               C   +   O₂    →    CO₂

learn more:

Chemical reaction brainly.com/question/3953793

#learnwithBrainly

4 0
3 years ago
Two asteroids collide and stick together. The first asteroid has a mass of 15\times 10^3\,\mathrm{kg}15×10 3 kg and is initially
statuscvo [17]

Answer:

Final speed is 900.06 m/s at 0.2215^{\circ}  

Solution:

As per the question:

Mass of the first asteroid, m = 15\times 10^{3}\kg

Mass of the second asteroid, m' = 20\times 10^{3}\kg

Initial velocity of the first asteroid, v = 770 m/s

Initial velocity of the second asteroid, v' = 1020 m/s

Angle between the two initial velocities, \theta = 20^{\circ}

Now,

Since, the velocities and hence momentum are vector quantities, then by the triangle law of vector addition of 2 vectors A and B, the resultant is given by:

\vec{R} = \sqrt{A^{2} + 2ABcos\theta + B^{2}}

Thus applying vector addition and momentum conservation, the final velocity is given by:

(m + m')v_{final} = \sqrt{(mv)^{2} + 2(mv)(m'v')cos20^{\circ} + (m'v')^{2}}                               (1)

Now,

(m +m')v_{final} = (35\times 10^{3})v_{final}

(mv)^{2} = (15\times 10^{3}\times 770)^{2} = 1.334\times 10^{14}

(m'v')^{2} = (20\times 10^{3}\times 1020)^{2} = 4.16\times 10^{14}

2(mv)(m'v')cos20^{\circ} = 2(15\times 10^{3}\times 770)(20\times 10^{3}\times 1020)cos20^{\circ} = 4.43\times 10^{14}

Now, substituting the suitable values in eqn (1), we get:

v_{final} = 900.06\ m/s

Now, the direction for the two vectors is given by:

\theta = sin^{- 1} \frac{m'v'sin20^{\circ}}{(m + m')v_{final}}

\theta = sin^{- 1} \frac{20\times 10^{3}\times 1020sin20^{\circ}}{(35\times 10^{3})\times 900.06} = 0.2215^{\circ}

5 0
3 years ago
The raising and lifting the ball by kicking is called
Minchanka [31]

The raising and lifting the ball by kicking is a B) Scoop

6 0
3 years ago
Verdah, Hetav and Dhinesh are undertaking an investigation into the motion of wooden blocks in their Physics class. Their aim is
kow [346]

Answer:

u can find answer in quora

Explanation:

4 0
3 years ago
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