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avanturin [10]
2 years ago
12

You are working with a 3 T MRI scanner with maximum gradient strength of 40 mT/m in all 3 axes (x,y,z). Your acquisition uses ma

ximum gradient strength to minimize the duration of the data acquisition window. When the Gx is the only gradient that is turned on, what is the rotation frequency for spins located at x=5cm, y=5cm? The gyromagnetic ratio is γ=42.576 MHz/T

Physics
1 answer:
inn [45]2 years ago
7 0

Answer:

Rotational frequency=ω/2\pi

Explanation:

Hence rotational frequency will be = 13.55 kHz

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(1) The wavelength of the wave is 1.164 m.

(2) The  velocity of the wave is 23.7 m/s.

(3) The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

<h3> Wavelength of the wave</h3>

A general wave equation is given as;

y(x, t) = A sin(Kx - ωt)

<h3>Velocity of the wave</h3>

v = ω/K

From the given wave equation, we have,

y(x, t) = 0.048 sin(5.4x - 128t)

v = ω/K

where;

  • ω corresponds to 128
  • k corresponds to 5.4

v = 128/5.4

v = 23.7 m/s

<h3>Wavelength of the wave</h3>

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λ = (2π)/(5.4)

λ = 1.164 m

<h3>Maximum speed of the wave</h3>

v(max) = Aω

where;

  • A is amplitude of the wave
  • ω is angular speed of the wave

v(max) = (0.048)(128)

v(max) = 6.14 m/s

Thus, the wavelength of the wave is 1.164 m.

The  velocity of the wave is 23.7 m/s.

The maximum speed in the y-direction of any piece of the string is 6.14 m/s.

Learn more about wavelength here: brainly.com/question/10728818

#SPJ1

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