Answer:
9 × 10⁻³ mol·L⁻¹s⁻¹
Explanation:
Data:
k = 1 × 10⁻³ L·mol⁻¹s⁻¹
[A] = 3 mol·L⁻¹
Calculation:
rate = k[A]² = 1 × 10⁻³ L·mol⁻¹s⁻¹ × (3 mol·L⁻¹)² = 9 × 10⁻³ mol·L⁻¹s⁻¹
Answer:
See details below
Explanation:
The balanced reaction equation is given below:
+
→
+ 
Mole fraction of CO2 to H20
= 8/10 = 
Mole ratio of C4H10 to CO2 is 2:8 = 1:4
1 mole of n-butane - 38.12 g
4 moles - ?
= 152.48g fuel consumed.