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3 years ago

What does wavelength refer to?

Chemistry

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

Wavelength, distance between corresponding points of two consecutive waves. ... Wavelength is usually denoted by the Greek letter lambda (λ); it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f.

Explanation:

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The phase after waxing gibbous is: half- moon full moon crescent moon new moon

Molodets [167]

full moon comes after waxing gibbous then waning gibbous

8 0

3 years ago

Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force.

NemiM [27]

Answer:

Explanation:

To form hydrogen bondings between the molecules, the compound needs a highly electronegative atom (usually N, O, or F) bonded with a hydrogen atom;

and that the highly electronegative atom has lone pair outermost shell electrons.

In the 5 options, only B (CH3OH) has an N, O, or F atom that has lone pair outermost shell electrons (2 lone pairs on each O atom), so it can form hydrogen bonds within its molecules.

Hydrogen bonds are stronger than the van der Waals' forces between its molecules (that exist regardless of whether there are hydrogen bonds).

4 0

3 years ago

A compound is 21.6% Mg, 21.4% C, and 57.0% O. What is the empirical formula of the compound?

nignag [31]

Answer:

Compound x = $MgC_{2}O_{4}$

Explanation:

Let the compound be x

Assuming we have a 100g of compound x

Given the following data;

Magnesium, Mg = 21.6% = 21.6g

Carbon, C = 21.4% = 21.4g

Oxygen, O = 57.0% = 57.0g

Now, we would find the amount of moles for each element.

Atomic mass of Mg = 24.30g

Atomic mass of C = 12.01g

Atomic mass of O = 16.00g

Amount of moles for Mg;

21.6*(1/24.30) = 0.89mol

Amount of moles for C;

21.4*(1/12.01) = 1.78mol

Amount of moles for O;

57.0*(1/16.00) = 3.56mol

We then divide by the smallest to find the ratio;

0.89/0.89 = 1 Mol of Mg

1.78/0.89 = 2 Mol of C

3.56/0.89 = 4 Mol of O

Therefore, the ratio of Mg, C and O is 1:2:4.

Compound x = $MgC_{2}O_{4}$

Hence, the empirical formula of the compound is $MgC_{2}O_{4}$

7 0

3 years ago

Consider the following four pairs of molecules. You may use 1H-NMR, 13C-NMR, or IRspectroscopyto differentiate the structures, b

GREYUIT [131]

Answer:

The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.

Explanation:

See the attached file for explanation

4 0

3 years ago

What is special about nitrogen , and what is its main function in the atmosphere

blagie [28]

Nitrogen makes about 78% of the air we breathe. Nitrogen is extremely important in living things. It forms the building blocks of proteins. We need proteins because they make up our skin and hair. Proteins also help us digest food. We get our nitrogen from plants, and plants get it from bacteria in the soil. Our atmosphere provides life with the nitrogen it needs.

5 0

4 years ago